In alphabet series, some alphabets are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

gfe _ ig _ eii _ fei _ gf _ ii

The series is gfeii / gfeii / gfeii / gfeii. Thus, the pattern gfeii is repeated

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84, 78, 72, 66, 60, 54, 48, ?, ?

What numbers should come next?

What numbers should come next?

In this simple subtraction series, each number is 6 less than the previous number.

Rule = (1st number), (1st no. - 6 = 2nd no.), (2nd no. - 6 = 3rd no.). . .

Now in our case,

(84), (84 - 6 = 78), (78 - 6 = 72), (72 - 6 = 66), (66 - 6 = 60), (60 - 6 = 54), (54 - 6 = 48), (48 - 6 = 42), (42 - 6 = 36).

So the answer is B = 42, 36.

The present ages of 3 persons are in proportion 3 : 4 : 5. After 5 years, the sum of their age is 75. Find their present age in years.

Let their present ages be 3x, 4x and 5x years respectively.

Then, (3x+ 5) + (4 x + 5 ) + ( 5 x + 5 ) =75

12 x = 60

x = 5

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so, the present ages are 10 years, 15 years and 20 years respectively.

The present ages of three Ladies are in proportion 4:7:9. Eight years ago, the sum of their ages eight years ago(in years).

Let their present ages be 4x,7x and 9x years respectively.

Then,(4x-8)+(7x-8)+(9x-8)=76

20x=100

x=5

Their present ages are 12 years ,27 years and 37 years respectively.

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All the six members of a family A, B, C, D,
E and F are travelling together. B is the son of C but C is not the mother of
B, A and C are a married couple. E is the brother of C. D is the daughter of A.
F is the brother of B. How many male members are there in the family?

Option: (D)

B is the son of C but C is not the mother of B means C is the father of B. A is married to C means A is the mother of B. F is brother of B means F is son of A and C. D is daughter of A means D is daughter A and C. A is the mother and hence female. B is the son and hence male. C is the husband and hence male. D is the daughter and hence female. E is the brother and hence male. F is the son and hence male. So , there are four males.

.In following alphabet series , one term missing as shown by question mark . Choose missing term from options.

AD, EH, IL, ?, QT

The first and second letter of each term are moved four steps forward to obtain the corresponding letters of the next term.

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Look at this series: 80, 10, 70, 15, 60, . . .

What number should come next?

What number should come next?

This is an alternating addition and subtraction series.

In the first pattern, 10 is subtracted from each number to arrive at the next.

In the second, 5 is added to each number to arrive at the next.

First pattern (80) (80 - 10 = 70) (70 - 10 = 60) (60 - 10 = 50)

Second pattern (10) (10 + 5 = 15) (15 + 5 = 20)

So the answer is 20..

A family consists of six children naming P,Q,R,X,Y and Z. Q is the son R but R is not the mother of Q. P and R are married couples. Y is brother of R. X is the daughter of P. Z is the brother of P. How many children does P have?

Q is the son of R but R is not the mother. So,P is married to R . So, P is the wife of R and the mother of Q. X is daughter of P and hence of R and so she is the sister of Q. Y is the brother of R and Z is the brother of P. Clearly Q is the son of P and X is daughter of P. so, P has two children. .

The average of six consecutive odd numbers is 61. What is the difference between the highest and lowest numbers:

Let's 6 consecutive odd numbers are:

3,5,7,9,11,13

Lowest term is 3 and highest is 13

13-3=10

So difference of 10 will remain the same in the consecutive series numbers.

In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. shg, rif, qje, pkd, ?

The first and third letters of each term are moved one step backward and the second letter is moved one step forward to obtain the corresponding letters of the next term.

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Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

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