Preperation of Five Minute Test

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Question No 1

A child was accompanying a woman. On being asked who the boy was, the woman said, His mother was the only daughter of my mother. How has the boy related to the woman?

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Solution!
Woman's mother's only daughter means she is talking about herself. So she is the mother of the child..

Question No 2

100/101 = ?

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Solution!
100/101 = 0.990099.

Question No 3

The Average age of a class of 22 subjects in 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?

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Solution!
Total age of all students = 22 * 21 = 462! !Total age of all students + age of the teacher = 23 * 22 = 506! !Age of the teacher = 506 - 462 = 44.

Question No 4

0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , ?

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Solution!
Add 1, 3, 5, 7, etc..

Question No 5

ESSAY is to THESIS as ARTICLE is to..

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Solution!
No answer description available for this question..

Question No 6

Elated is to despondent as enlightened is to..

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Solution!
Elated is the opposite of despondent; enlightened is the opposite of ignorant..

Question No 7

A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is

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Solution!
Man's rate in still water = (15 - 2.5) km/hr!= 12.5 km/hr! !Man's rate against the current = (12.5 - 2.5) km/hr!= 10 km/hr.

Question No 8

The angle between the minute hand and the hour hand of a clock when the time is 4:20, is ?

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Solution!
Angle traced by hour hand in 13/3 hrs = (360/12 * 13/3) = 130 degree! !Angle traced by minute hand in 20 min = (360/60 * 20) = 120 degree! !So, required angle = 130 - 120 = 10 degree.

Question No 9

The ages of C and D are in 6/11 and E is 6 years younger than D. If the sum of ages is 134, then what is the age of D?

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Solution!
Given that!C/D = 6/11!C = (6/11)D ...(1)! !and!C+D+E = 134! !As E is 6 years younger from D so we can put D-6 instead of D!C+D+D-6 = 134!C+2D = 140!Put value of C from equation(1)!(6/11)D+2D = 140!6D+22D = 140!28D = 1540!D = 55! !Hence D is 55 years old..

Question No 10

A train always has

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Solution!
No answer description available for this question..

Question No 11

Anil's swimming speed in still water is 14 km/h and speed of water is 4 km/h. How long will it take him to go upstream 50 km?

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Solution!
Anil's swimming speed in still water = u = 14 Km/h!Speed of water = v = 4 Km/h!Total upstream speed = u-v = 14-10 = 10 Km/h!Distance to cover = S = 50Km! !time = distance/speed!By putting values!time = t = 50/10 = 5 hours.

Question No 12

X can do a piece of work in 40 days.He works at it for 8 days and then Y finished it in 16 days.How long will they together take to complete the work?

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Solution!
Work done by X in 8 days = (1/40 * 8)!= 1/5! !Remaining work = (1 - 1/5)!4/5! !Now, 4/5 work is done by Y in 16 days.! !Whole work will be done by Y in (16 * 5/4)!= 20 days! !So,!X's 1 day's work = 1/40!Y's 1 day's work = 1/20! !(X + Y)'s 1 day's work = (1/40 + 1/20) = 3/40! !Hence, X and Y will together complete the work in 40/3 days.

Question No 13

Find the odd man out.

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Solution!
All except Swing have 3 vowels..

Question No 14

A man pointing to Stephen said, "I have no brother or sister, but that man's father is my father's son". What is he to Stephen?

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Solution!
The man who is pointing has no brother so Son of his father means he himself.! !So, he is Stephen's father..

Question No 15

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is

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Solution!
Suppose, number of articles bought =L.C.M. of 6 and 5!= 30! !C.P. of 30 articles = (5/6) * 30 = Rs. 25! !S.P. of 30 articles = (6/5)*30! = Rs. 36! !Hence, Gain % = (11/25) * 100 = 44%.
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