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Question No 1

Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is

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Solution!
Ratio of times taken by Sakshi and Tanya = 125/100 = 5/4! !Suppose Tanya takes x days to do the work.! !5/4 = 20/x!x = (4*20)/5! !x = 16 days.! !Hence, Tanya takes 16 days to complete the work..

Question No 2

The present age of A is 45 yeras. 5 years ago the age of A was 5 times the age of his son B. How old is B now?

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Solution!
Given that!A = 45! !and!A-5 = 5(B-5)!40 = 5B-25!65 = 5B!B = 13! !Hence B is 13 years old now..

Question No 3

What will be the day of the week 15th August, 2010?

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Solution!
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)! !Odd days in 1600 years = 0! !Odd days in 400 years = 0! !9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days = 4 odd days.! !From January to 15 August (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days! !227 days = (32 weeks + 3 days) = 3 odd days.! !Total number of odd days = (0 + 0 + 4 + 3) = 7.! !Hence, Given day is Sunday..

Question No 4

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

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Solution!
Ratio of times taken by A and B = 100/130 = 10/13! !Suppose B takes x days to do the work.! !Then, 10/13 = 23/x!x = (23*13)/10!x = 299/10! !A's 1 day's work = 1/23! !B's 1 day's work = 10/299! !(A + B)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13! !Therefore, A and B together can complete the work in 13 days..

Question No 5

0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , ?

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Solution!
Add 1, 3, 5, 7, etc..

Question No 6

A cigarette case is full of cigars and cigarettes, probability of a cigarette is 8/15. What is the ratio of cigars to cigarettes.

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Solution!
In 15 cigars and cigarettes there are 8 cigarettes So ratio between cigars and cigarettes is 8/7. Which means there are 8 cigarettes and 7 cigars..

Question No 7

If P + Q means P is the brother of Q; P x Q means P is the wife of Q and P % Q means P is the daughter of Q then which of the following means D is the uncle of A?

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Solution!
No answer description available for this question..

Question No 8

A is as much younger than B and he is older than C. If the sum of the ages of B and C is 50 years, what is definitely the difference between B and A's age?

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Solution!
Age of C < Age of A < Age of B! !Given that sum of the ages of B and C is 50 years.! !Let's take B's age = x and C's age = 50-x! !Now we need to find out B's age - A's age.!But we cannot find out this with the given data..

Question No 9

Tiger is to Forest as Otter is to?

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Solution!
As Tiger is found in Forest similarly Otter is found in the water..

Question No 10

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train is

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Solution!
Let the speed of each train be x m/sec.! !Then, relative speed of the two trains = 2x m/sec.! !So, 2x = (120 + 120)/12!2x = 20!x = 10! !Hence, Speed of each train = 10 m/sec = 10 * (18/5)!= 36 km/hr.

Question No 11

SYNTHESIS is to PARTS as CONFLUENCE is to..

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Solution!
No answer description available for this question..

Question No 12

Pointing to a girl Sandeep said, "She is the daughter of the only sister of my father." How is sandeep related to the girl?

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Solution!
The girl is the daughter of the sister of Sandeep's father.! !Hence, the girl is the cousin or Sandeep is the cousin of the girl..

Question No 13

A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

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Solution!
Rate downstream = (1/10) * 60 km/hr = 6 km/hr! !Rate upstream = 2 km/hr! !Speed in still water = (1/2)(6 + 2) km/hr = 4 km/hr! !Hence, Required time = 5/4 hrs = 1 hr 15 min..

Question No 14

Choose the word which is different from the rest.

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Solution!
All except Gazel are animals found in the mountains..

Question No 15

A song always has

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Solution!
No answer description available for this question..
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