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Question No 1

Pointing to a woman, Abhijit said, "Her granddaughter is the only daughter of my brother." How is the woman related to Abhijit?

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Solution!
Daughter of Abhijit's brother = niece of Abhijit.! !Thus the granddaughter of the woman is Abhijit's niece.! !Hence, the woman is the mother of Abhijit..

Question No 2

CRITERIA is to DATA as CRITERION is to..

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Solution!
No answer description available for this question..

Question No 3

Which number is the odd one out, 8, 27, 64, 100, 125, 216, 343

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Solution!
All others are perfect cube of any number but 100 is not the perfect cube of any number..

Question No 4

A train travelling at the speed of 10m/s can cross a bridge in 23 seconds. If length of the train is 120 meters. What is length of the bridge?

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Solution!
Speed = v = 10m/s!Time = t = 23s!Length of train = L1 = 120m!Length of bridge = L2 = ?! !t = (L1+L2)/v!By putting values!23 = (120+L2)/10!L2 = 230 - 120 = 110m! !Hence bridge is 110m long..

Question No 5

A can do a certain work in the same time in which B and C together can do it.If A and B together could do it in 10 days and C alone in 50 days,then B alone could do it in

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Solution!
(A + B)'s 1 day's work = 1/10! !C's 1 day's work = 1/50! !(A + B + C)'s 1 day's work = (1/10 + 1/50) = 6/50 = 3/25...(1)! !A's 1 day's work = (B + C)'s 1 day's work .... (2)! !From (1) and (2), we get!2 * (A's 1 day's work) = 3/25! !A's 1 day's work = 3/50! !So, B's 1 day's work (1/10 - 3/50) = 2/50 = 1/25! !Hence, B alone could do the work in 25 days..

Question No 6

0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , ?

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Solution!
Add 1, 3, 5, 7, etc..

Question No 7

A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

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Solution!
Rate downstream = (1/10) * 60 km/hr = 6 km/hr! !Rate upstream = 2 km/hr! !Speed in still water = (1/2)(6 + 2) km/hr = 4 km/hr! !Hence, Required time = 5/4 hrs = 1 hr 15 min..

Question No 8

64% of the children in school are girls.What percentage are boys?

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Solution!
100 - 64 = 36%.

Question No 9

Find the odd man out.

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Solution!
Others are means of communication..

Question No 10

A bus covers a distance of 60 Km in 1.5 hr. How far it would travel in half hour.

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Solution!
Distance covered in 1.5 hr = 60! !Distance covered in 1 hr = 60/1.5 = 40 Km! !Distance Covered in 0.5 hr = 40 * 0.5 = 20.

Question No 11

A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is

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Solution!
Let the speed of the stream be x km/hr.! !Then,!Speed downstream = (15 + x) km/hr! !Speed upstream = (15 - x) km/hr! !So, [30/(15 + x)] + [30/(15 - x)] = 9/2!900/(225 - x*x) = 9/2! !x = 5 km/hr.

Question No 12

Seen through a mirror, the arms of a clock show 9:30 what is the actual time?

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Solution!
No answer description available for this question..

Question No 13

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in

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Solution!
(B + C)'s 1 day's work = (1/9 + 1/12) = 7/36! !Work done by B and C in 3 days = (7/36 * 3)!= 7/12! !Remaining work = (1 - 7/12)!= 5/12! !Now, 1/24 work is done by A in 1 day.! !So, 5/12 work is done by A in (24 * 5/12) = 10 days..

Question No 14

X is 4 times as old as y. 4 years ago, X was 10 times as old as Y. What will be the ratio of their ages 6 years hence?

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Solution!
Given that!X = 4Y ...(1)! !and!X-4 = 10(Y-4)!X-4 = 10Y-40!X-10Y = -36!10Y-X = 36 ...(2)! !Put value of X from equation(1) in equation(2)!10Y-4Y = 36!6Y = 36!Y = 6! !Put value of Y in equation(1)!X = 4*6!X = 24! !After 6 years!Y = 24+6!Y = 30!and!X = 6+6!X = 12! !Ratio between X and Y is!30/12 = 5/2! !Hence after 6 years ratio between ages of X and Y will be 5/2..

Question No 15

What is the angle between the hands of a clock at 1 o'clock?

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Solution!
At 1 o'clock the minute hand points to the 12 and the hour hand points to the 1.! !So we need to find the angle between the 12 and the 1.! !There are 12 total numbers on the clock and total angle on complete turn of the clock is 360 degree, so each one must be 360/12 = 30 degree.! !So the angle between the hands of a clock at 1 o'clock is 30 degree..

Question No 16

Which of the following is not a leap year?

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Solution!
The century divisible by 400 is a leap year.! !So, The year 600 is not a leap year..

Question No 17

By how many degrees does the minute hand move in the same time, in which the hour hand move by 280?

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Solution!
28 * 2 * 6 = 336 degree.

Question No 18

Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?

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Solution!
Given that! !(i)The difference of age b/w R and Q = The difference of age b/w Q and T!(ii) (R + T) = 50! !So,R - Q = Q - T! !(R + T) = 2Q! !Now given that, (R + T) = 50! !So, 50 = 2Q and therefore Q = 25! !Question is (R - Q) = ?! !Here we know the value(age) of Q (25), but we don't know the age of R.! !Therefore, (R-Q) cannot be determined..

Question No 19

APOCRYPHAL is to CERTAINTY as CHAOTIC is to..

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Solution!
No answer description available for this question..

Question No 20

100 , 96.75 , 93.5 , 90.25 , 87 , ?

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Solution!
Deduct 3.25 each time..

Question No 21

Find the correctly spelt word.

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Solution!
No answer description available for this question..

Question No 22

Which one of the following a 'Drama' must have?

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Solution!
No answer description available for this question..

Question No 23

Pointing to Varman, Madhav said, "I am the only son of one of the sons of his father." How is Varman related to Madhav?

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Solution!
Madhav is the only son of one of the sons of Varman's father! !So, Either Varman is the father or uncle of Madhav..

Question No 24

The average age of A and B is 20. If C were to replace A, the average would be 19, and if B was replaced by C, the average would be 21. The age of C is

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Solution!
Given that!(A+B)/2 = 20!A+B = 40 ...(1)! !and!(C+B)/2 = 19!C+B = 38 ...(2)! !and!(A+C)/2 = 21!A+C = 42 ...(3)! !Put value of A from equation(1) in equation(3)!(40-B)+C = 42!C-B = 2 ...(4)! !By simultaneously solving equation(2) and equation(4)!C = 20! !Hence C is 20 years old..

Question No 25

0 , 100 , 6 , 94 , 12 , 88 , 18 , 82 , ? , ?

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Solution!
There are two sequences interwoven.! !Add 6 starting at 0 and deduct 6 starting at 100..

Question No 26

A takes twice as much time as B or thrice as much time as C to finish a piece of work.Working together,they can finish the work in 2 days.B can do the work alone in

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Solution!
Suppose A, B and C take x, x/2, x/3 days respectively to finish the work.! !Then,!(1/x + 2/x + 3/x) = 1/2!6/x = 1/2!x=12! !So, B takes (12/2) = 6 days to finish the work..

Question No 27

If the product of 4 consecutive integers is 120, which is greater?

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Solution!
5*4*3*2 = 120.

Question No 28

P, the daughter of K is married to G, X and G are brothers, on the basis of this information tell how P is related to G.

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Solution!
"P, the daughter of K is married to G" means P is wife of G..

Question No 29

Choose the word which is different from the rest.

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Solution!
All except Scallop live in shells..

Question No 30

When R is divided by 7 remainder is 3. What is the remainder when 3R is divided by 7?

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Solution!
No answer description is available for this question..
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