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Question No 1

An article was sold at a loss of 15% for $476. What is the cost price of the article?

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Solution!
Let cost price of the article is x.!15% of x = (15x)/100 = 3x/20! !Now!(3x/20) + 476 = x!3x+9520 = 20x!9520 = 17x!x = 560! !Hence cost price of the article is $560..

Question No 2

Find the correctly spelt word.

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Solution!
No answer description available for this question..

Question No 3

If M x N means M is the daughter of N; M + N means M is the father of N; M % N means M is the mother of N and M - N means M is the brother of N then P % Q + R - T x K indicates which relation of P to K?

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Solution!
P % Q = P is the mother of Q! !Q + R = Q is the father of R! !R - T = R is the brother of T! !Hence, Q is the father of T! !T x K = T is the daughter of K! !Hence, Q is the husband of K.! !Therefore, P is the mother-in-law of K..

Question No 4

A man can row 1 km upstream in 20 minutes, and downstream in 15 minutes. What is the speed of the current?

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Solution!
20 minutes = 20/60 = 1/3 hours!Upstream distance covered in 1/3 hours = 1 Km!Upstream distance covered in 1 hour = 1/(1/3) = 3 Km!Upstream speed = y = 3 Km/h! !Now!15 minutes = 15/60 = 1/4 hours!Downstream distance covered in 1/4 hours = 1 Km!Downstream distance covered in 1 hour = 1/(1/4) = 4 Km!Downstream speed = 4 Km/h! !speed of water = (1/2)*(4-3) = 1/2 = 0.5 Km/h.

Question No 5

A's son B is married with C whose sister D is married to E the brother of B. How D is related to A?

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Solution!
Since E is the brother of B! !Therefore, A is the father of E! !but D is the wife of E.! !Hence, D is the daughter-in-law of A..

Question No 6

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

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Solution!
Speed = (240/24) = 10m/s! !Hence, Required time = (240+650)/10!= 89 seconds.

Question No 7

If P $ Q means P is the brother of Q; P # Q means P is the mother of Q; P * Q means P is the daughter of Q in A # B $ C * D, who is the father?

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Solution!
A is the mother of B, B is the brother of C and C is the daughter of D.! !Hence, D is the father..

Question No 8

In the first 10 overs of a cricket game the run rate was only 3.2 What should be the run rate in the remaining 40 overs to reach the target of 282?

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Solution!
3.2 * 10 = 32! !After 10 overs score is 32.! !Remaining score = 282 - 32 = 250! !Required rate = 250 / 40 = 6.25 runs/over.

Question No 9

Kamal was 4 times as old as his son 8 years ago. After 8 years, Kamal will be twice as old as his son. Find out the present age of Kamal.

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Solution!
Let the age of the son before 8 years = x! !Then age of Kamal before 8 years ago = 4x! !After 8 years, Kamal will be twice as old as his son! !4x + 16 = 2(x + 16)!x = 8! !Present age of Kamal = 4x + 8 = (4*8) + 8 = 40.

Question No 10

A and B are married couple. X and Y are brothers. X is the brother of A. How is Y related to B.

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Solution!
X and Y both are brothers of A!which means both are Brother-in-law of B..

Question No 11

FRANKENSTEIN is to SHELLEY as DRACULA is to..

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Solution!
No answer description available for this question..

Question No 12

If a light flashes every 6 seconds, how many times will it flash in 3/4 of an hour?

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Solution!
3/4 of an hour = 3/4 * 60 * 60 = 2700! !Light will flash in 6 seconds = 2700/6 = 450 times.

Question No 13

Which number is the odd one out, 10, 25, 45, 54, 60, 75, 80

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Solution!
Each of the numbers except 54 is multiple of 5..

Question No 14

Which one of the following is always found in 'Wonder'?

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Solution!
No answer description available for this question..

Question No 15

Multiply 86 by 9 and add to 13 multiplied by 6.

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Solution!
86 * 9 = 774! !13 * 6 = 78! !774 + 78 = 852.

Question No 16

If p is and odd integer and 7p > 50 and 3p < 35 then p is?

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Solution!
7*11 = 77 (greater than 35) and 3*7 = 33 (lesser than 35)! !*Note that 8 is also true but in question it is explicitly said that integer must be odd..

Question No 17

A man rowing a boat covers an average distance of 7.5 km/h. What is the distance covered after 40 minutes?

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Solution!
Distance covered in 60 minutes = 7.5 Km!Distance covered in 1 minute = 7.5/60 = 1/8 Km! !Distance covered in 40 minutes = (1/8)*40 = 5 Km.

Question No 18

0 , 100 , 6 , 94 , 12 , 88 , 18 , 82 , ? , ?

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Solution!
There are two sequences interwoven.! !Add 6 starting at 0 and deduct 6 starting at 100..

Question No 19

Pointing towards a man, a woman said, "His mother is the only daughter of my mother." How is the woman related to the man?

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Solution!
Only daughter of my mother = myself.! !Hence, the woman is the mother of the man..

Question No 20

20 years ago my age was 1/3 of what it is now. What is my present age?

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Solution!
Let my present age is x.! !Given that!x-20 = (1/3)x!3x-60 = x!2x = 60!x = 30! !Hence my present age is 30 years..

Question No 21

By selling a car for Rs. 495000 an agent gains 10%. What was his cost?

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Solution!
Let cost price of the car is x.!10% of x = 10x/100 = x/10! !Now!495000 - (x/10) = x!4950000 - x = 10x!4950000 = 11x!x = 450000.

Question No 22

Find the odd man out.

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Solution!
Others are means of communication..

Question No 23

1 , 1 , 2 , ? , 24 , 120 , 720

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Solution!
Multiply by 1, 2, 3 and so on....

Question No 24

100 , 96.75 , 93.5 , 90.25 , 87 , ?

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Solution!
Deduct 3.25 each time..

Question No 25

John's mother is sister of David's brother. What is John to David?

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Solution!
David is brother of John's mother.! !So John is nephew of David..

Question No 26

Six years ago, the ratio of the ages of Kunal and Sagar was 6/5. Four years hence, the ratio of their ages will be 11/10. What is Sagar's age at present?

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Solution!
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.! !Then,![(6x + 6) + 4]/[(5x + 6) + 4] = 11/10!10(6x + 10) = 11(5x + 10)!5x = 10!x = 2! !Hence, Sagar's present age = (5x + 6) = 16 years..

Question No 27

Find the odd man out.

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Solution!
All except office are residential places..

Question No 28

What is 5/8 of 240?

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Solution!
(5/8) * 240 = 150.

Question No 29

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

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Solution!
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years!= 4x years.! !(4x + 8) = 5/2 (x+8)!8x + 16 = 5x + 40!3x = 24!x = 8! !Hence, required ratio = (4x+16)/(x+160)!= 48/24 = 2.

Question No 30

How many non-leap years are there from 1801 to 1900?

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Solution!
Leap year comes after 4 years!In one century there will be 24 leap years! !Hence, there will be 76 non leap years from 1801 to 1900..

Question No 31

11th of April falls on Tuesday, what day will the last day of the month April occurs.

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Solution!
Tuesday will be on 11, 18 and 25 then 30th April will be on Sunday..

Question No 32

What will be the day of the week 15th August, 2010?

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Solution!
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)! !Odd days in 1600 years = 0! !Odd days in 400 years = 0! !9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days = 4 odd days.! !From January to 15 August (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days! !227 days = (32 weeks + 3 days) = 3 odd days.! !Total number of odd days = (0 + 0 + 4 + 3) = 7.! !Hence, Given day is Sunday..

Question No 33

PENURY is to MONEY as STARVATION is to..

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Solution!
No answer description available for this question..

Question No 34

Choose the word which is different from the rest.

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Solution!
All except Feathers are organs for movement in different organisms..

Question No 35

By selling a Television for $572 Adam lost 12%. What was the cost price of the television?

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Solution!
Let cost price of the television is x.!12% of x = 12x/100 = 3x/25! !Now!(3x/25)+572 = x!3x + 14300 = 25x!14300 = 22x!x = 650! !Hence cost price of the television is $650..

Question No 36

REASON is to SFBTPO as THINK is to?

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Solution!
As,!R + 1 = S!E + 1 = F!A + 1 = B!S + 1 = T!O + 1 = P!N + 1 = O! !Similarly,!T + 1 = U!H + 1 = I!I + 1 = J!N + 1 = O!K + 1 = L.

Question No 37

3 years ago, the average age of C and D was 18 years. With E joining them, the average becomes 22 years. How old is E now?

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Solution!
Given that![(C-3)+(D-3)]/2 = 18!C-3+D-3 = 36!C+D = 42 ...(1)! !and also given that!(C+D+E)/3 = 22!C+D+E = 66! !Put value of C+D from equation(1)!42+E = 66!E = 66-42!E = 24! !Hence E is 24 years old now..

Question No 38

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in

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Solution!
(B + C)'s 1 day's work = (1/9 + 1/12) = 7/36! !Work done by B and C in 3 days = (7/36 * 3)!= 7/12! !Remaining work = (1 - 7/12)!= 5/12! !Now, 1/24 work is done by A in 1 day.! !So, 5/12 work is done by A in (24 * 5/12) = 10 days..

Question No 39

Find the odd man out.

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Solution!
No answer description available for this question..

Question No 40

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is

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Solution!
Let the length of the train be x metres and its speed by y m/sec.! !Then, x/y = 15!y = x/15! !So, (x+100)/25 = x/15!15(x + 100) = 25x!15x + 1500 = 25x!1500 = 10x!x = 150 m.

Question No 41

A man was accompanying a girl, on being asked who the girl was the man said, "Her father was the only son of my father". What was the girl to man?

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Solution!
If I am a boy and I am only son of my father it means I am talking about myself.! !Same is the case here man is father of the girl..

Question No 42

Bill's age is 1/3 of Mike's age, who is 60% of James' age. Tom is twice as old as Mike. What is the ratio of Bill's age to Tom's age?

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Solution!
Let Bill's age is Z, Mike's age is Y and Tom's age is X.! !Given that!Z = (1/3)Y!and!Y = (60/100)X!Y = (6/10)X! !Tom's Age is double of Mike's age mean his age is 2y.!Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is![(1/3)Y] / 2Y!(1/3)*(1/2) = 1/6! !Hence ratio between Bill's and Tom's age is 1/6..

Question No 43

Choose the word that is a necessary part of the word "desert"

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Solution!
A desert is an arid tract of land. Not all deserts are flat (choice d). Not all deserts have cacti or oases (choices a and c)..

Question No 44

Architect is to Building as Sculptor is to?

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Solution!
As 'Architect' makes 'Building'! similarly 'Sculptor' makes 'Statue'..

Question No 45

The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is

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Solution!
Speed downstream = (15 + 3) kmph = 18 kmph! !Distance travelled = 18 * (12/60)km = 3.6 km.

Question No 46

By selling an article for $200 shopkeeper looses 20%. What is cost price of the article?

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Solution!
Let cost price of the article is x.! !20% of x = (x*20)/100 = x/5! !Now!(x/5) + 200 = x!x+1000 = 5x!4x = 1000!x = 250! !Hence cost price of the article is 250..

Question No 47

FRANKENSTEIN is to SHELLEY as DRACULA is to..

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Solution!
No answer description available for this question..

Question No 48

How many degrees will the minute hand move, in the same time in which the second hand move 4800

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Solution!
Minute hand covers 480/60= 80.

Question No 49

Price of a car increased from $400000 to $420000. What is the percentage increase?

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Solution!
Increase in price = 420000 - 400000! = 20000! !Percentage increase = (20000/400000)*100! = 5%.

Question No 50

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is

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Solution!
Let the speed of the second train be x km/hr.! !Relative speed = (x + 50) km/hr!= (x+50)*(5/18) m/s!= (250+5x)18 m/s! !Distance covered = (108 + 112) = 220 m! !So, 220/[(250 + 5x) /18] = 6!250 + 5x = 660! !Hence, x = 82 km/hr.

Question No 51

MENDEL is to NEWTON as GENETICS is to..

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Solution!
No answer description available for this question..

Question No 52

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

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Solution!
Let the mother's present age be x years.! !Then,! the person's present age = (2/5)x years.! !(2/5)x + 8 = (1/2)(x + 8)!2(2x + 40) = 5(x + 8)!x = 40!.

Question No 53

Which number is the odd one out, 8, 27, 64, 100, 125, 216, 343

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Solution!
All others are perfect cube of any number but 100 is not the perfect cube of any number..

Question No 54

Subtract 369 from 1250.

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Solution!
1250 - 369 = 881.

Question No 55

Choose the word that is a necessary part of the word "book"

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Solution!
The necessary part of a book is its pages; there is no book without pages. Not all books are fiction (choice a), and not all books have pictures (choice c). Learning (choice d) may or may not take place with a book..

Question No 56

What is the angle between the minute hand and the hour hand when the time is 1540 hours?

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Solution!
Hour hand is nearly at 3!Minute hand is at 8! !Angle between 3 and 8 is 150 degree.! !In 40 Minutes hour hand will move 1/2 * 40 = 20 degree! !Hence, Angle between hands is 150 - 20 = 130 degree.

Question No 57

What is 3/4 of 92 plus 13?

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Solution!
(3/4) * 92 = 69! !69 + 13 = 82.

Question No 58

0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , ?

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Solution!
Add 1, 3, 5, 7, etc..

Question No 59

10 women can complete a work in 7 days and 10 children take 14 days to complete the work.How many days will 5 women and 10 children take to complete the work?

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Solution!
1 woman's 1 day's work =1/70! !1 child's 1 day's work =1/140! !(5 women + 10 children)'s 1 day's work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7! !Hence, 5 women and 10 children will complete the work in 7 days..

Question No 60

A ship travels at the speed of 20 km/h upstream and 24 km/h downstream. What is the speed of boat in still water?

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Solution!
Upstream speed = y = 20 Km/h!Downstream speed = x = 24 Km/h!Speed of ship = (1/2)*(x+y)!=(1/2)*(20+24) = 22 Km/h.
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