# Age Problem

#### Question No 1

A father is 15 times as old as his son. however, 18 years later, he will be only thrice as old as the son. What is the father's present age?

#### Select the correct answer

Solution!
Let present age of the son is x and present age of Father is y.

Given that
y = 15x
15x-y = 0 ...(1)

and also given that
y+18 = 3(x+18)
y+18 = 3x+54
y-3x = 36 ...(2)

By simultaneously solving equation(1) and equation(2)
y = 45

Hence father's present age is 45 years..

#### Question No 2

A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?

#### Select the correct answer

Solution!
Let the present age of the son = x years

Then present age the man = (x+24) years

Given that in 2 years, man's age will be twice the age of his son

(x+24) +2 = 2(x+2)
x = 22.

#### Question No 3

A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B?

#### Select the correct answer

Solution!
Let the age of C = x.

Then

Age of B = 2x

Age of A = 2 + 2x

The total age of A,B and C =27

(2+2x) + 2x + x = 27
5x = 25
B's age = 2x = 2 * 5 = 10.

#### Question No 4

The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be

#### Select the correct answer

Solution!
Let the present ages of son and father be x and (60 -x) years respectively.

Then,
(60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14

Hence, Son's age after 6 years = (x+ 6)
= 20 years.

#### Question No 5

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

#### Select the correct answer

Solution!
Let the mother's present age be x years.

Then,
the person's present age = (2/5)x years.

(2/5)x + 8 = (1/2)(x + 8)
2(2x + 40) = 5(x + 8)
x = 40
.

#### Question No 6

The Average age of a class of 22 students is 21 years.The average increased by 1 when the teacher's age also included.What is the age of the teacher?

#### Select the correct answer

Solution!
No answer description available for this question..

#### Question No 7

The product of the ages of two class fellows is 24. If the greater fellow is 3/2 times the smaller one, then the age of the smaller fellow is

#### Select the correct answer

Solution!
Let present age of the greater fellow is x and present age of smaller fellow is y.

Given that xy = 24 ...(1)
and

x = (3/2)y
Put value of x in equation(1).

(3/2)y^2 = 24
y^2 = 24*(2/3)
y^2 = 16
y = 4

Hence age of smaller fellow is 4 years..

#### Question No 8

The sum of the ages of a son and a father is 64. After 4 years the age of father will be three times that of his son's. The age of father is

#### Select the correct answer

Solution!
Let present age of son is x and present age of father is y.

Given that
x+y = 64 ...(1)

and
y+4 = 3(x+4)
y+4 = 3x + 12
y-3x = 8 ...(2)

Put value of x from equation(1) in equation(2)

y-3(64-y) = 8
y-192+3y = 8
4y = 200
y = 50

Hence present age of the father is 50 years..

#### Question No 9

The sum of the ages of two children is 12 and their product is 32. The age of elder one is

#### Select the correct answer

Solution!
Let age of younger child is x and age of elder child is y.

Given that
x+y = 12 ...(1)

and
xy = 32
x = 32/y

Put value of x in equation(1)
(32/y)+y = 12
32+(y^2) = 12y
(y^2)-12y+32 = 0
(y^2)-8y-4y+32 = 0
y(y-8)+4(y-8) = 0
(y-8)(y+4) = 0
y = -4 (impossible)
or
y = 8

Hence age of elder child is 8 years..

#### Question No 10

The difference of the ages of two brothers is 2 and the difference of the square of their ages is 16. The age of smaller one is?

#### Select the correct answer

Solution!
Let present age of elder brother is y and present age of younger brother is x.

Given that
y-x = 2 ...(1)

and
(y^2)-(x^2) = 16
(y+x)(y-x) = 16

Put value of (y-x) from equation(1)
2(y+x) = 16
y+x = 8 ...(2)

By simultaneously solving equation(1) and equation(2) we have
y = 5
and
x = 3

Hence present age of younger brother is 3 years..

#### Question No 11

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

#### Select the correct answer

Solution!
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years
= 4x years.

(4x + 8) = 5/2 (x+8)
8x + 16 = 5x + 40
3x = 24
x = 8

Hence, required ratio = (4x+16)/(x+160)
= 48/24 = 2.

#### Question No 12

If 1/2 x year ago A was 12 and 1/2 x years from now he will be 2x years old, how old will he be 3x years from now?

#### Select the correct answer

Solution!
Given that
A-(1/2)x = 12
2A-x = 24 ...(1)
and
A+(1/2)x = 2x
A+(1/2)x-2x = 0
A+(x-4x)/2 = 0
A-(3/2)x = 0
2A-3x = 0 ...(2)
By simultaneously solving equation(1) and (2) we have
x = 12
and
A = 18

Now
3x = 3*12 = 36

After 3x years A will be
18+36 = 54 years old.

#### Question No 13

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?

#### Select the correct answer

Solution!
Let the age of the youngest child = x

Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12).

Then,
X + (x+3) + (x+6) + (x+9) + (x+12) = 50
5x + 30 =50
5x = 20
x = 20/5 = 4.

#### Question No 14

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. What is the present age of the mother?

#### Select the correct answer

Solution!
Let the present age of the person = x

Then present age of the mother = 5x/2

Given that , after 8 years, the person will be one-half of the age of his mother.

(x + 8) = (1/2)(5x/2 + 8)
2x + 16 = 5x/2 + 8
x/2 = 8
x = 16

Present age of the mother = 5x/2
= 5 * 16/2 = 40.

#### Question No 15

Ages of A and B are in ratio 8/7. 27 years ago their ages were in the ratio 5/4. The age of B is

#### Select the correct answer

Solution!
Given that
A/B = 8/7 ...(1)

and
(A-27)/(B-27) = 5/4
5B-135 = 4A-108 ...(2)

From equation(1) we have
A = (8/7)B

Put value of A in equation(2)
5B-135 = 4*[(8/7)B]-108
5B-27 = (32/7)B
5B-(32/7)B = 27
(35B-32B)/7 = 27
3B = 189
B = 63

Hence the age of B is 63 years..

#### Question No 16

Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?

#### Select the correct answer

Solution!
Given that

(i)The difference of age b/w R and Q = The difference of age b/w Q and T
(ii) (R + T) = 50

So,R - Q = Q - T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25

Question is (R - Q) = ?

Here we know the value(age) of Q (25), but we don't know the age of R.

Therefore, (R-Q) cannot be determined..

#### Question No 17

Sachin's age after 15 years will be 5 times his age 5 years back. Find out the present age of Sachin?

#### Select the correct answer

Solution!
Let the present age of Sachin = x

Then (x+15) = 5(x-5)
4x = 40
x = 10.

#### Question No 18

Six years ago, the ratio of the ages of Kunal and Sagar was 6/5. Four years hence, the ratio of their ages will be 11/10. What is Sagar's age at present?

#### Select the correct answer

Solution!
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then,
[(6x + 6) + 4]/[(5x + 6) + 4] = 11/10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2

Hence, Sagar's present age = (5x + 6) = 16 years..

#### Question No 19

A father is 3 years older than 3 times the age of his son. If the sum of their ages is 31 years, how old was father 3 years ago?

#### Select the correct answer

Solution!
Let present age of son is x and present age of father is y.

Given that
y = 3x+3 ...(1)

and
x+y = 31
x = 31-y

Put value of x in equation(1)
y = 3(31-y)+3
y = 93-3y+3
4y = 96
y = 24

Three years ago
y = 24-3
y = 21

Hence father was 21 years old 3 years ago..

#### Question No 20

3 years ago, the average age of C and D was 18 years. With E joining them, the average becomes 22 years. How old is E now?

#### Select the correct answer

Solution!
Given that
[(C-3)+(D-3)]/2 = 18
C-3+D-3 = 36
C+D = 42 ...(1)

and also given that
(C+D+E)/3 = 22
C+D+E = 66

Put value of C+D from equation(1)
42+E = 66
E = 66-42
E = 24

Hence E is 24 years old now..

#### Question No 21

A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27.How old is B?

#### Select the correct answer

Solution!
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

So, (2x + 2) + 2x + x = 27
5x = 25
x = 5

Hence, B's age = 2x = 10 years.

#### Question No 22

The ages of X and Y are in the ratio 7/4. If the sum of their present ages is 55, then the age of X is

#### Select the correct answer

Solution!
Given that
x/y = 7/4 ...(1)

and
x+y = 55 ...(2)

From equation(1)
4x = 7y
y = (4/7)x

Put value of y in equation(2)
x + (4/7)x = 55
(7x+4x)/7 = 55
11x = 385
x = 35

Hence the age of x is 35 years..

#### Question No 23

Bill's age is 1/3 of Mike's age, who is 60% of James' age. Tom is twice as old as Mike. What is the ratio of Bill's age to Tom's age?

#### Select the correct answer

Solution!
Let Bill's age is Z, Mike's age is Y and Tom's age is X.

Given that
Z = (1/3)Y
and
Y = (60/100)X
Y = (6/10)X

Tom's Age is double of Mike's age mean his age is 2y.
Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is
[(1/3)Y] / 2Y
(1/3)*(1/2) = 1/6

Hence ratio between Bill's and Tom's age is 1/6..

#### Question No 24

Tina is twice as old as David. 15 years ago, Tina's age was 5 times the age of David. What is the present age of Tina?

#### Select the correct answer

Solution!
Let David's age is x and Tina's age is y.

Given that
y = 2x
y-2x = 0 ...(1)

and also given that
y-15 = 5(x-15)
y-15 = 5x-75
y-5x = -60 ...(2)

By simultaneously solving equation(1) and equation(2)
y = 40

Hence Tina's present age is 40 years..

#### Question No 25

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was?

#### Select the correct answer

Solution!
Let the son's present age be x years. Then, (38 - x) = x

2x = 38
x = 19

Hence, Son's age 5 years back (19 - 5) = 14 years..

#### Question No 26

A is as much younger than B and he is older than C. If the sum of the ages of B and C is 50 years, what is definitely the difference between B and A's age?

#### Select the correct answer

Solution!
No answer description available for this question..

#### Question No 27

The present age of A is 45 yeras. 5 years ago the age of A was 5 times the age of his son B. How old is B now?

#### Select the correct answer

Solution!
Given that
A = 45

and
A-5 = 5(B-5)
40 = 5B-25
65 = 5B
B = 13

Hence B is 13 years old now..

#### Question No 28

A mother's age after 5 years, will be twice the age of her daughter. The difference of their ages is 19. What is the age of mother?

#### Select the correct answer

Solution!
Let present age of daughter is x and present age of mother is y.

Given that
y+5 = 2(x+5)
y+5 = 2x+10
5-10 = 2x-y
y-2x = 5 ...(1)

and also given that
y-x = 19 ...(2)

By simultaneously solving equation(1) and equation(2) we can find
y = 33

Hence mothers present age is 33 years..

#### Question No 29

Sandeep's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1/5. What is Sandeep's father's age at present?

#### Select the correct answer

Solution!
Let the age of Sandeep and his father before 10 years be x and 5x respectively.

Given that Sandeep's age after six years will be three-seventh of his father's age

x + 16 = (3/7)(5x + 16)
7x + 112 = 15x + 48
8x = 64
x = 8

Sandeep's father's present age = 5x + 10
= 5*8 + 10 = 50.

#### Question No 30

Ten years ago a father was seven times as old as his son, two years hence, twice his age will be equal to five times his son's. What is the present age of son?

#### Select the correct answer

Solution!
Let present age of son is x and present age of father is y.

Given that
y-10 = 7(x-10)
y-10 = 7x-70
y-7x = -70+10
7x-y = 60 ...(1)

and also given that
2(y+2) = 5(x+2)
2y+4 = 5x+10
2y-5x = 6 ...(2)By simultaneously soving equation(1) and equation(2)
x = 14

Hence present age of son is 14 years..

#### Question No 31

Ten years ago Akram was thrice as old as Aslam was, but 10 years hence, he will be only twice as old. What is Akram's present age?

#### Select the correct answer

Solution!
Let Aslam's present age is x and Akram's present age is y.

Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)

and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)

By simultaneously solving equation(1) and equation(2)
y=70

Hence Akram's present age is 70 years..

#### Question No 32

The Average age of a class of 22 subjects in 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?

#### Select the correct answer

Solution!
Total age of all students = 22 * 21 = 462

Total age of all students + age of the teacher = 23 * 22 = 506

Age of the teacher = 506 - 462 = 44.

#### Question No 33

X is 4 times as old as y. 4 years ago, X was 10 times as old as Y. What will be the ratio of their ages 6 years hence?

#### Select the correct answer

Solution!
Given that
X = 4Y ...(1)

and
X-4 = 10(Y-4)
X-4 = 10Y-40
X-10Y = -36
10Y-X = 36 ...(2)

Put value of X from equation(1) in equation(2)
10Y-4Y = 36
6Y = 36
Y = 6

Put value of Y in equation(1)
X = 4*6
X = 24

After 6 years
Y = 24+6
Y = 30
and
X = 6+6
X = 12

Ratio between X and Y is
30/12 = 5/2

Hence after 6 years ratio between ages of X and Y will be 5/2..

#### Question No 34

20 years ago my age was 1/3 of what it is now. What is my present age?

#### Select the correct answer

Solution!
Let my present age is x.

Given that
x-20 = (1/3)x
3x-60 = x
2x = 60
x = 30

Hence my present age is 30 years..

#### Question No 35

The ratio of A's age and B's age is 3/7, and the difference of their ages is 16 years. Find the age of B.

#### Select the correct answer

Solution!
Given that
A/B = 3/7 ...(1)

and
B-A = 16 ...(2)
Put value of A from equation(1) in equation(2)
B-(3/7)B = 16
(7B-3B)/7 = 16
4B = 112
B = 28

Hence Age of B is 28 years..

#### Question No 36

Meena is thrice as old as Sheraz. Fatima will be twice as old as Meena 6 years hence. Six years ago Sheraz was five years old. What is Fatima's present age?

#### Select the correct answer

Solution!
Let present age of Sheraz is x and present age of Fatima is y.

So,
Meena's age = 3x

Given that
y+6 = 2(3x+6) ...(1)
and
x-6 = 5
x = 11

Put value of x in equation(1)

y+6 = 2(33+6)
y+6 = 78
y = 72

Hence Fatima's present age is 72 years..

#### Question No 37

Ten years ago, P was half of Q in age. If the ratio of their present ages is 3/4, what will be the total of their present ages?

#### Select the correct answer

Solution!
Let the present age of P and Q be 3x and 4x respectively.

Ten years ago, P was half of Q in age.

(3x - 10) = 1/2 * (4x - 10)
6x - 20 = 4x - 10
2x = 10
x = 5

total of their present ages
= 3x + 4x = 7x = 7 * 5
= 35.

#### Question No 38

The sum of the present ages of a mother and daughter is 63. Three years back if the age of the mother was double that of the daughter, then the present age of the daughter is

#### Select the correct answer

Solution!
Let mother's present age is x and daughters present age is y

Given that
x+y = 63 ...(1)
and

x-3 = 2(y-3)
x-3 = 2y-6
x-2y = -6+3
x-2y = -3 ...(2)

By simultaneously solving equation(1) and equation(2) We'll find
y = 22

Hence present age of the daughter is 22 years..

#### Question No 39

One year ago, the ratio of Sooraj's and Vimal's age was 6/7 respectively. Four years hence, this ratio would become 7/8. How old is Vimal?

#### Select the correct answer

Solution!
Let take the age of Sooraj and Vimal, 1 year ago as 6x and 7x respectively.

Given that, four years hence, this ratio would become 7/8.

(6x + 5)/(7x + 5) = 7/8
48x + 40 = 49x + 35
x = 5

Vimal's present age = 7x + 1 = 7*5 + 1 = 36.

#### Question No 40

The ratio of the ages of two friends A and B is 3/2. However if the age of A is decreased by 10 and that of B is increased by 10 then the original ratio is reversed. Age of A is

#### Select the correct answer

Solution!
Given that
A/B = 3/2
2A = 3B
2A-3B = 0 ...(1)

and also given that
(A-10)/(B+10) = 2/3
3A-30 = 2B+20
3A-2B = 50 ...(2)

By simultaneously solving equation(1) and equation(2)
A = 30

Hence age of A is 30 years..

#### Question No 41

C's mother was four times as old as C ten years ago. After 10 years she will be twice as old as C is now. How old C is now?

#### Select the correct answer

Solution!
Let C's present age is x and his mother's age is y.

Given that
y = 4(x-10)
y = 4x-40
4x-y = 40 ...(1)

and
y+10 = 2x
2x-y = 10 ...(2).

By simultaneously solving equation(1) and equation(2) we find
x = 15

Hence C is 15 years old..

#### Question No 42

The average age of A and B is 20. If C were to replace A, the average would be 19, and if B was replaced by C, the average would be 21. The age of C is

#### Select the correct answer

Solution!
Given that
(A+B)/2 = 20
A+B = 40 ...(1)

and
(C+B)/2 = 19
C+B = 38 ...(2)

and
(A+C)/2 = 21
A+C = 42 ...(3)

Put value of A from equation(1) in equation(3)
(40-B)+C = 42
C-B = 2 ...(4)

By simultaneously solving equation(2) and equation(4)
C = 20

Hence C is 20 years old..

#### Question No 43

In 1975, A was thrice as old as B but in 1979, A was only twice as old as B was. How old was A in 1985?

#### Select the correct answer

Solution!
Let A's age in 1985 was X.

Given that
X-10 = 3(B-10)
X-10 = 3B-30
3B-X = 20 ...(1)

and
X-6 = 2(B-6)
X-6 = 2B-12
2B-X = 6 ...(2)

By simultaneously solving equation(1) and (2) we have
X = 22

Hence A's age in 1985 was 22 years..

#### Question No 44

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is

#### Select the correct answer

Solution!
Let the ages of father and son 10 years ago be 3x and x years respectively.

Then,
(3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20
So, 3x + 10 = 70
and x + 10 = 30

Hence, ratio is 70/30 = 7/3..

#### Question No 45

A man's age is three times his son's. In 15 years it will be double that of his son's. How old is the son now?

#### Select the correct answer

Solution!
Let Son's age is x
Mans Age = 3x

Given that
3x+15 = 2(x+15)
3x+15 = 2x+30
3x-2x = 30-15

x = 15

Hence son is 15 years old..

#### Question No 46

Kiran is younger than Bineesh by 7 years and their ages are in the respective ratio of 7 / 9, how old is Kiran?

#### Select the correct answer

Solution!
Let the ages of Kiran and Bineesh are 7x and 9x respectively

7x = 9x-7
x = 7/2 = 3.5

Kiran's age = 7x
= 7 * 3.5 = 24.5.

#### Question No 47

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. What is the ratio of their present ages?

#### Select the correct answer

Solution!
Let the age of the son before 10 years = x
and age of the father before 10 years = 3x

Now we can write as (3x + 20) = 2(x + 20)
x = 20

Age of Father the son at present = x + 10
= 20 + 10 = 30

Age of the father at present = 3x + 10
= 3 * 20 + 10 = 70

Required ratio = 70/30 = 7/3.

#### Question No 48

Kamal was 4 times as old as his son 8 years ago. After 8 years, Kamal will be twice as old as his son. Find out the present age of Kamal.

#### Select the correct answer

Solution!
Let the age of the son before 8 years = x

Then age of Kamal before 8 years ago = 4x

After 8 years, Kamal will be twice as old as his son

4x + 16 = 2(x + 16)
x = 8

Present age of Kamal = 4x + 8 = (4*8) + 8 = 40.

#### Question No 49

The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person?

#### Select the correct answer

Solution!
Let's take the present age of the elder person = x

and the present age of the younger person = x - 16

(x - 6) = 3 (x-16-6)
x - 6 = 3x - 66
2x = 60
x = 60/2 = 30.

#### Question No 50

The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A?

#### Select the correct answer

Solution!
Given that A+B = 12 + B + C

A - C = 12 + B - B = 12

C is younger than A by 12 years..

#### Question No 51

Kamal's age is 1/6 of his father's age. If kamal's 8th birthday was celebrated 2 years ago, what is father's present age?

#### Select the correct answer

Solution!
Let Kamal's present age is x and his father's present age is y.

Given that
y = 6x ...(1)

and
x-2 = 8
x = 10

Put value of x in equation(1)
y = 6*10
y = 60

Hence father's present age is 60 years..

#### Question No 52

A's age is 3/4 of that of B's. Two years ago A's age was 1/2 of what B will be in 4 years. How old is A now?

#### Select the correct answer

Solution!
Given that
A = (3/4)B ...(1)

and
A-2 = (1/2)(B+4)
2A-4 = B+4
2A-B = 8

Put value of B from equation(1)
2A-(4/3)A = 8
6A-4A = 24
2A = 24
A = 12

Hence A is 12 years old now..

#### Question No 53

Present ages of Sameer and Anand are in the ratio of 5/4 respectively. Three years hence, the ratio of their ages will become 11/9 respectively. What is Anand's present age in years?

#### Select the correct answer

Solution!
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then,
(5x+3)/(4x+3) = 11/9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6

nand's present age = 4x = 24 years.

#### Question No 54

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, what was the son's age five years back?

#### Select the correct answer

Solution!
Let the son's present age be x years.

Then
(38 - x) = x

2x = 38
x = 38/2 = 19

Son's age 5 years back = 19-5 = 14 years.

#### Question No 55

The ages of C and D are in 6/11 and E is 6 years younger than D. If the sum of ages is 134, then what is the age of D?

#### Select the correct answer

Solution!
Given that
C/D = 6/11
C = (6/11)D ...(1)

and
C+D+E = 134

As E is 6 years younger from D so we can put D-6 instead of D
C+D+D-6 = 134
C+2D = 140
Put value of C from equation(1)
(6/11)D+2D = 140
6D+22D = 140
28D = 1540
D = 55

Hence D is 55 years old..

#### Question No 56

Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7/9, how old is Sachin?

#### Select the correct answer

Solution!
Let Rahul's age be x years.

Then,
Sachin's age = (x - 7) years.

(x-7)/x = 7/9
9x - 63 = 7x
2x = 63
x = 31.5

Hence, Sachin's age =(x - 7)= 24.5 years.

#### Question No 57

John is 35 years older than his new born cousin. How old will the cousin be, when his age is 1/6 that of John's?

#### Select the correct answer

Solution!
We can simply check it from options. If John's cousins age is 7 then John's age is 42
and
1/6 0f 42 = 7
Hence 7 fulfills the required condition..

#### Question No 58

A is as much younger than B and he is older than C. If the sum of the ages of B and C is 50 years, what is definitely the difference between B and A's age?

#### Select the correct answer

Solution!
Age of C < Age of A < Age of B

Given that sum of the ages of B and C is 50 years.

Let's take B's age = x and C's age = 50-x

Now we need to find out B's age - A's age.
But we cannot find out this with the given data..

#### Question No 59

At present, the ratio between the ages of Arun and Deepak is 4/3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?

#### Select the correct answer

Solution!
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.

Then,
4x + 6 = 26
4x = 20
x = 5

Hence, Deepak's age = 3x = 15 years..

#### Question No 60

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?

#### Select the correct answer

Solution!
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then,
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4

Hence, Age of the youngest child = x = 4 years.
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