P is the Brother of R;

Q is the son of P ;

T is the brother of S;

S is the daughter of R.

Who are the cousins of Q?

Option (D)

T is the brother of S, who is the daughter of R. So, T and S are the children of R. Now, P is the brother of R and Q is the son of P. So, T and S are the cousins of Q.

In following alphabet series , one term missing as shown by question mark . Choose missing term from options.

Z, L, X, J, V, H, T, F, ?, ?

The given sequence consists of two series -- Z, X, V, T, ? and L, J, H, F, ?, both consisting of alternate letters in a reverse order.

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Salesman, engineer and accountant. There are two married couples in the family. D, the salesman is married to the lady teacher. The doctor is married to the lawyer. F, the accountant is the son of B and brother of E. C, the lawyer is the daughter in law of A. E is the unmarried engineer. A Is the grandmother of F. What is the profession of A.

C is the daughter in law of A who is the grandmother of F means C is the mother of F. But F is the son of B. So, B is C's husband. But C, the lawyer, is married to the doctor. So, B is the doctor. F, the accountant, will be the son of B and C. E is the unmarried engineer. So, the other married couple can be that of grandmother of F i.e, A and D. But D, the salesman, is married to the lady teacher. So, D, the salesman, is the grandfather of F, father of B and the husband of A, the lady teacher. A is the lady teacher..

How many prime numbers are there in the list 1, 12, 123, 1234, 12 345, 123 456 ?

It is important to remember that we do not regard 1 as a prime number. We see that 12, 1234 and 123 456 are not prime numbers because they are divisible by 2. Also, 123 is not a prime number because it is divisible by 3, and 12 345 is not a prime number because it is divisible by 5. So there are no prime numbers in the list.

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A man and his wife have three sons and every of the son have a sister. How many are there in the family?

There is only one girl since it says that every sons have a sister, if there's only one girl. She will be a sister to all the three sons. So 3 sons + 1 sister + both the parents= 6 member in the family..

The ages of three sisters are in proportion 6x,7x,8x. After six years the sum of their ages is 50. Find their present ages?

Let their present ages be 6x,7x,8x.

Then , (6x+6)+(7x+6)+(8x+6)=50

21x+18=50

21x=50-18

21x=32

x=2

So, their present ages be 12,14,16.

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