The sum of Tony and Teddy age is thrice their mother age . Tony is two years younger than Teddy if the age of mother is 42 . Find the difference between mother and younger son.

Teddy=x elder son

Tony=x-2 younger sonGiven condition

3(Tony+Teddy)=Mother

3(x-2+x)=42

6x-6=42

6x=48

X=8

Tony = 6

Teddy=8

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There are six children playing football namely A, B, C, D,E nad F.

A and E are brothers. F is the sister of E. C is the only son of A's uncle.

B and D are the daughter of the brother of C's father.

How many male players are there?

As, given A and E are brothers. Hence female. C is the son and hence male. B and D are daughter and hence female. Thus, there are three males..

What is the unit digit in the product (365 x 659 x 771)?

Unit digit in 34 = 1 Unit digit in (34)16 = 1

Unit digit in 365 = Unit digit in [ (34)16 x 3 ] = (1 x 3) = 3

Unit digit in 659 = 6

Unit digit in 74 Unit digit in (74)17 is 1.

Unit digit in 771 = Unit digit in [(74)17 x 73] = (1 x 3) = 3

Required digit = Unit digit in (3 x 6 x 3) = 4

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In a 100m race a once with a speed of 1.66 metre per second. If a give a start of 4 minute to be and still beats him by 12 seconds. What is the speed of B?

Time taken by a to cover hundred metres =60 seconds

Since a gives a start of 4 minutes then time taken by b =72 seconds

B takes 72 second to cover 96 meters

speed of B =96 / 8

72 = 1.33 meter per second.

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Hira has 30 bangles, 18 of which are pink and 12 of which are white. Saher has 20 bangles, all of them either pink or white. If the ratio of the pink bangles to the white bangles is the same for both Hira and Saher, then Hira has how many more pink bangles then Sahar?

Hira bangles ratio :

pink: white

18: 12

3:2

Saher are also with the same ratio as Hira

pink :white Total

3:. 2: 20

3 x + 2 x = 20 => 5 x 20 => X = 4

3 X = 3 (4 )= 12 pink bangles

Hira have: 18 - 2 = 6 bangles more than Sahar.

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