Salesman, engineer and accountant. There are two married couples in the family. D, the salesman is married to the lady teacher. The doctor is married to the lawyer. F, the accountant is the son of B and brother of E. C, the lawyer is the daughter in law of A. E is the unmarried engineer. A Is the grandmother of F. What is the profession of A.

C is the daughter in law of A who is the grandmother of F means C is the mother of F. But F is the son of B. So, B is C's husband. But C, the lawyer, is married to the doctor. So, B is the doctor. F, the accountant, will be the son of B and C. E is the unmarried engineer. So, the other married couple can be that of grandmother of F i.e, A and D. But D, the salesman, is married to the lady teacher. So, D, the salesman, is the grandfather of F, father of B and the husband of A, the lady teacher. A is the lady teacher..

When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?

x = 13p + 11 and x = 17q + 9

13p + 11 = 17q + 9

17q - 13p = 2

q =(2 + 13p) /17

The least value of p for which q =(2 + 13p) /17is a whole number is p = 26

x = (13 x 26 + 11)

= (338 + 11)

= 349

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Look at this series: 58, 52, 46, 40, 34, . . .

What number should come next?

What number should come next?

This is a simple subtraction series.

Each number is 6 less than the previous number.

(58 - 6 = 52), (52 - 6 = 46), (46 - 6 = 40), (40 - 6 = 34),(34 - 6 = 28)

So the answer is B = 28..

The average of 6 quantities is 4. The average of 3 them is 3. What is the average of the remaining three numbers?

The average of 6 quantities is 4.

Therefore ,the sum of the 6 quantities is 6 Ã— 4 = 24.

The average of three of these 3 quantities is 3.

Therefore, the sum of these three quantities = 3 Ã— 3 = 9

The sum of the remaining three quantities = 24 - 9 = 15 .

Average of these three quantities = 15 / 3 = 5.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. J2Z, K4X, 17V, ?, H16R, M22P

The first letters in odd numbered terms from series J, I, H and in even numbered terms from the series K, L, M. The sequence followed by the numbers is + 2, + 3, + 4, + 5, + 6. The third letter of each term is moved two steps backward to obtain the third letter of the next term.

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