In alphabet series, some alphabets are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

cab _ a _ c _ bc _ bc _ b _ ab

The series is cab / cab / cab / cab / cab. Thus, the pattern cab is repeated.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. 2Z5, 7Y7, 14X9, 23W11, 34V13, ?

The first numbers in the terms follow the sequence + 5, + 7, + 9, + 11, + 13. The middle letters form the series Z, Y, X, W, V, U.

The last numbers from the series 5, 7, ,9 , 11, 13, 15.

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A family consists of six children naming P,Q,R,X,Y and Z. Q is the son R but R is not the mother of Q. P and R are married couples. Y is brother of R. X is the daughter of P. Z is the brother of P. How many children does P have?

Q is the son of R but R is not the mother. So,P is married to R . So, P is the wife of R and the mother of Q. X is daughter of P and hence of R and so she is the sister of Q. Y is the brother of R and Z is the brother of P. Clearly Q is the son of P and X is daughter of P. so, P has two children. .

All the 6 members of a family A.B.C.D.E.and F are traveling together . B is the son or C but C is not the mother of B ,A and C are a married couple . E is the brother of C.D is the daughter of A.F is the brother of B.

How many male members are there in the family?

B is the son of C is not the mother of B means C is the father of B.A is married to C means A is the mother of B .F is brother 0f B means F is son of A and C.D is daughter of A means D is daughter A and C. A is the mother and hence female .B is the son and hence male. C is the husband and hence female. D is the daughter and hence female. E is the brother and hence male. F is the son and hence male. So, there are four males..

What is (999 âˆ’ 99 + 9) Ã· 9?

First work out the value of the expression in the brackets and then divide the result by 9. This gives (999 âˆ’ 99 + 9) Ã· 9 = 909 Ã· 9 = 101. Alternatively, we can first divide each number in the bracket by 9 and then evaluate the resulting expression. This gives (999 âˆ’ 99 + 9) Ã· 9 = (111 âˆ’ 11 + 1) = 101.

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The present age of three persons are in proportion 4:7:9. Eight years ago the sum of their ages is 76. Find their present ages?(in years)

Let the present ages be 4x,7x,9x years respectively.

Then (4x-8)+(7x-8)+(9x-8)=76

20x=100

x=100/20

x=5

There present ages be 20,35,45 years respectively.

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