A man has a daughter and a son. The son is is three years older than the daughter. In one year the man will be six time as old as the daughter is now. In ten years the man will be fourteen years older than the combined ages of his children at that time. what is the man's present age?

Let's the age of daughter=x

age f son = x+3

age of father now=6x-1

condition:

M+0={(S+D)+ 10}+14]

6x-1=[{(x+3)+10}+14]

4x=28

x=7

Father's age=(6x-7)-1=41

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In following number series, either one term is missing or is incorrect.

Choose correct answer from options 1, 5, 11, 19, 29, 55

Choose correct answer from options 1, 5, 11, 19, 29, 55

The correct sequence is + 4, + 6, + 8, + 10, ....

So, next term after 29 = 29 + 12 = 41.

The term after 41 will then be (41 + 14) i.e. 55.

41 is missing..

In a 100m race a once with a speed of 1.66 metre per second. If a give a start of 4 minute to be and still beats him by 12 seconds. What is the speed of B?

Time taken by a to cover hundred metres =60 seconds

Since a gives a start of 4 minutes then time taken by b =72 seconds

B takes 72 second to cover 96 meters

speed of B =96 / 8

72 = 1.33 meter per second.

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Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

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