A person travel at the rate of 60 miles per hour and cover 300 miles in 5 hours. If he reducing is paid by 10 miles per hour how long will it take to cover the same distance?

Original speed= 60 miles per hour

If the speed is reduced by 10 miles per hour.

Then the new speed= 50 miles per hour

Distance to be covered= 300 miles

Time= distance/speed

Time=300/50

Time=6 hr

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A + B means A is the father of B.

A -B means A is the wife of B.

A Ã—B means A is the brother of B.

A Ã·B means A is the daughter of B.

If P Ã·R + S + Q , which of the following is true?

PÃ·R+S+Q means P is the daughter of R who is the father of S who is the father of Q i.e.P is the sister of the father (S) of Q i.e. P is the aunt of Q..

A family consists of six children naming P,Q,R,X,Y and Z. Q is the son R but R is not the mother of Q. P and R are married couples. Y is brother of R. X is the daughter of P. Z is the brother of P. How many children does P have?

Q is the son of R but R is not the mother. So,P is married to R . So, P is the wife of R and the mother of Q. X is daughter of P and hence of R and so she is the sister of Q. Y is the brother of R and Z is the brother of P. Clearly Q is the son of P and X is daughter of P. so, P has two children. .

In a 100m race a once with a speed of 1.66 metre per second. If a give a start of 4 minute to be and still beats him by 12 seconds. What is the speed of B?

Time taken by a to cover hundred metres =60 seconds

Since a gives a start of 4 minutes then time taken by b =72 seconds

B takes 72 second to cover 96 meters

speed of B =96 / 8

72 = 1.33 meter per second.

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There are 6 persons A, B, C ,D E and F. C is the sister of F. B is the brother of E,s husband. D is the father of A and grand father of F. There are two fathers three brothers and a mother in the group. How many male members are there in the group?

D is father of A and grandfather of F. So, A is father of F. Thus D and A are the two fathers. C is the sister of F. So, C is the daughter of A . Since there is only one mother it is evident that E is the wife of A and hence the mother of C and C and F. so B is brother of A. There are three brothers. So F is the brother of C. A, the father is male. B, the brother, is male. C, the sister is female. D, the grandfather, is male. E, the mother, is female. F, the brother, is male. So, there are 4 male..

Salesman, engineer and accountant. There are two married couples in the family. D, the salesman is married to the lady teacher. The doctor is married to the lawyer. F, the accountant is the son of B and brother of E. C, the lawyer is the daughter in law of A . E is the unmarried engineer. A is the grandmother of F. Which of the following is one of the couples?

C is the daughter in law of A who is the grandmother of F means C is the mother of F. But F is the son of B. So, B is c's husband. But C, the lawyer, is married to the doctor. So, B is the doctor. F, the accountant, will be the son of B and C. E is the unmarried engineer. So, the unmarried couples can be that of grandmother of F i.e. A and D .But D, the salesman is married to the lady teacher. So, D, the salesman, is the grandfather of F, father of B and the husband of A, the lady teacher.

The two couples are C and B; and D and A which is none among the choices.

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A + B means A is the father of B ;

A - B means A is the wife of B ;

A x B means A is the brother of B ;

A Ã· B means A is the daughter of B.

If P - R x Q, which of the following is true?

Option (C)

P - R x Q means P is the wife of R who is the brother of Q i.e. P is the sister-in-law of Q.

Naresh

The ratio of two sister Alice and Betty is 3/2. Howere the age of Alice befor 15 years and that of Betty after 15 years than the original ratio is reserved. What is the age of Alice?

Let

Alice age's=A and Betty Age's=B

Given that

A / B =3/2

2A=3B

2A-3B=0.......(1)

And also given that

(A-15)/(B+15)=2/3

3A- 45= 2 b- 30

3A -2B= 75..... (2)

By solving both questions

A=45.

So Alice is 45 year old

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The sum of how many terms of the series 6 + 12 + 18 + 24 + ... is 1800 ?

This is an A.P. in which a = 6, d = 6 and Sn = 1800

Then, n/2[2a + (n - 1)d] = 1800

n/2[2 x 6 + (n - 1) x 6] = 1800

3n (n + 1) = 1800

n(n + 1) = 600

n2 + n - 600 = 0

n2 + 25n - 24n - 600 = 0

n(n + 25) - 24(n + 25) = 0

(n + 25)(n - 24) = 0

n = 24

Number of terms = 24.

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The ages of three sisters are in proportion 6x,7x,8x. After six years the sum of their ages is 50. Find their present ages?

Let their present ages be 6x,7x,8x.

Then , (6x+6)+(7x+6)+(8x+6)=50

21x+18=50

21x=50-18

21x=32

x=2

So, their present ages be 12,14,16.

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