John has 30 Marbles ,18 of which are red and 12 of which are blue. Jane has 20 Marbles all of them either red or blue. If the ratio of the red Marbles to the blue Marbles is the same for both John and jane, then John has how many more blue marbles than Jane?

John marble ratio:

read :blue

18 :12

3: 2

Jane Marbles are also with the same ratio as john.

Red: blue. total

3: 2. 20

3 X + 2 x = 20 = > 5 x = 20= >X = 4

2 X = 2( 4 )= 8 blue marbles

John have: 12 - 8 = 4 blue Marbles than jane

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To train starting at the same time from two station to 50 km apart and going in opposite directions cross each other at a distance of 170 km from one to two of the station. What is the ratio of their speeds?

In same time to cover 170 km at a kilometre respectively.

For the same time speed and distance is inversely proportional.

Suresh of the speed=17:80=17:8

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All the six members of a family A, B, C, D,
E and F are travelling together. B is the son of C but C is not the mother of
B, A and C are a married couple. E is the brother of C. D is the daughter of A.
F is the brother of B. How many male members are there in the family?

Option: (D)

B is the son of C but C is not the mother of B means C is the father of B. A is married to C means A is the mother of B. F is brother of B means F is son of A and C. D is daughter of A means D is daughter A and C. A is the mother and hence female. B is the son and hence male. C is the husband and hence male. D is the daughter and hence female. E is the brother and hence male. F is the son and hence male. So , there are four males.

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In following questions, one term in number series is incorrect.

Find out the incorrect number

1, 5, 5, 9, 7, 11, 11, 15, 12, 17

Find out the incorrect number

1, 5, 5, 9, 7, 11, 11, 15, 12, 17

The given sequence is a combination of two series:

I. 1, 5, 7, 11, 12 and

II. 5, 9, 11, 15, 17

The pattern in both I and II is + 4, + 2, + 4, + 2.

So, 12 is wrong and must be replaced by (11 + 2) i.e. 13..

In following questions, three sequence of alphabets/numerals are provided which correspond to each other in some way. Find out alphabets/numerals that come in the blank places.Choose the correct option

C B _ _ D _ B A B C C B _ _ 1 2 4 3 _ _ ? ? ? ? a _ a b _ c _ b _ _ _ _

Comparing position of capital letters, numbers and small letters, as we find:

a corresponds to C and 1 corresponds to a. So a and 1 corresponds to C.

b corresponds to A and 2 corresponds to b. So b and 2 corresponds to A.

Also, 4 corresponds to D.

So the remaining number i.e. 3 corresponds to B, So BCCB corresponds to 3, 1, 1, 3.

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In a 100m race a once with a speed of 1.66 metre per second. If a give a start of 4 minute to be and still beats him by 12 seconds. What is the speed of B?

Time taken by a to cover hundred metres =60 seconds

Since a gives a start of 4 minutes then time taken by b =72 seconds

B takes 72 second to cover 96 meters

speed of B =96 / 8

72 = 1.33 meter per second.

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A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?

Clearly, we have :

A = B - 3 ...(i)

D + 5 = E ...(ii)

A+C = 2E ...(iii)

B + D = A+C = 2E ...(iv)

A+B + C + D + E=150 ...(v)

From (iii), (iv) and (v), we get: 5E = 150 or E = 30.

Putting E = 30 in (ii), we get: D = 25.

Putting E = 30 and D = 25 in (iv), we get: B = 35.

Putting B = 35 in (i), we get: A = 32.

Putting A = 32 and E = 30 in (iii), we get: C = 28.

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Bombay Express left Delhi from Bombay at 14.30 hours, travelling at a speed of 60 km per hour and Rajdhani Express left. Delhi from Bombay on the same day at 16.30 hours, travelling at the speed of 80 kilometre per hour. How far away from Delhi will the two trains meet?

Suppose they meet x hours after 14.30 hours.

Then 60 x =80 (x-2) or x=8

Required distance=(60*8)km

=480 km.

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A can complete a work in 20 days. B can complete the same task in 15 days. B worked for 10 days and left the job. In how many days A alone can complete the work?

B:s 10 days work=(1/15)*10

=2/3

Remaining work=(1-2/3)=1/3

Now,1/20 work is done by A in 1 day.

Hence ,1/3 work is done by A in (20*1/3)=6.6

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