Which numbers comes next in the following series?

3, 13, 18, 23, 28, 33, ?, ?

3, 13, 18, 23, 28, 33, ?, ?

In this simple addition series, each number is 5 greater than the previous number.

Rule = (1st no.), (1st no. + 5 = 2nd no), (2nd no. + 5 = 3rd no) . . .

Now in our case

(3), (3 + 5 = 8), (8 + 5 = 13), (13 + 5 = 18), (18 + 5 = 23), (23 + 5 = 28), (28 + 5 = 33), (33 + 5 = 38), (38 + 5 = 43)

So the answer is C = 38, 43..

If the number 42573 * is exactly divisible by 72, then the minimum value of * is:

72 = 9 x8, where 9 and 8 are co-prime.

The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.

Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.

Required value of * is 6.

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John has 30 Marbles ,18 of which are red and 12 of which are blue. Jane has 20 Marbles all of them either red or blue. If the ratio of the red Marbles to the blue Marbles is the same for both John and jane, then John has how many more blue marbles than Jane?

John marble ratio:

read :blue

18 :12

3: 2

Jane Marbles are also with the same ratio as john.

Red: blue. total

3: 2. 20

3 X + 2 x = 20 = > 5 x = 20= >X = 4

2 X = 2( 4 )= 8 blue marbles

John have: 12 - 8 = 4 blue Marbles than jane

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The sum of Tony and Teddy age is thrice their mother age . Tony is two years younger than Teddy if the age of mother is 42 . Find the difference between mother and younger son.

Teddy=x elder son

Tony=x-2 younger sonGiven condition

3(Tony+Teddy)=Mother

3(x-2+x)=42

6x-6=42

6x=48

X=8

Tony = 6

Teddy=8

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In following alphabet series , one term missing as shown by question mark . Choose missing term from options.

JE, LH, OL, SQ, ?

The first letter of the first, second, third,... terms are respectively moved two, three, four,... steps forward while the second letters of three terms are respectivvely moved three, four, five,... steps forward to obtain the corresponding letters of the successive terms..

What is the unit digit in(795 - 358)?

Unit digit in 795 = Unit digit in [(74)23 x 73]

= Unit digit in [(Unit digit in(2401))23 x (343)]

= Unit digit in (123 x 343)

= Unit digit in (343)

= 3

Unit digit in 358 = Unit digit in [(34)14 x 32]

= Unit digit in [Unit digit in (81)14 x 32]

= Unit digit in [(1)14 x 32]

= Unit digit in (1 x 9)

= Unit digit in (9)

= 9

Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.

So, Option B is the answer.

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