Jimmy bought 60 Mangoes and 40 Apples. He found 30% of Mangoes and 10% of apples were overripe. Find the number of fruit in good condition.

Total fruit = 60 + 40 = 100

Overripe Mangoes = 30% of 60

= 30/100 x 60

=18

Overripe Apples = 10% of 40

= 10/100 x 40

=4

Total number of overripe fruit= 18+4=22

Therefore Number of fruit in good condition= 100-22= 78

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Choose or find odd letter group

VT , MQ , PR , DF , FG

Putting A = 1, B = 2, ....... and so on, we have:

VT = V + T = 22 + 20 = 42 (even);

MQ = M + Q = 13 + 17 = 30 (even);

PR = P + R = 16 + 18 =34 (even);

DF = D + F = 4 + 6 = 10 (even);

FG = F + G = 6 + 7 = 13 (odd).

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. AB, DEF, HIJK, ?, STUVWX

The number of letters in the terms goes on increasing by 1 at each step. Each term consists of letters in alphabetical order. The last letter of each term and the first letter of the next term are alternate..

Which term comes next in the series:

YEB, WFD, UHG, SKI, ?

YEB, WFD, UHG, SKI, ?

Clearly, the first letter of each term is moved two steps backward to obtain the first letter of the next term.

So, the first letter of the missing term will be Q.

The second letter of the first, second, third, fourth terms are respectively moved one, two, three and four steps forward to obtain the corresponding letter of the subsequent term.

So, the second letter in the missing term will be O.

The third letter is alternately moved two and three steps forward to obtain the corresponding letter of the subsequent term.

So, the third letter in the missing term will be L.

Thus, the missing term is QOL.

Hence, the answer is (A)..

The average age of a class of 22 subjects in 20 years. The average increased by 1 when teacher is included. What is the age of teacher?

Total age of students = 22x20=440

Total age of all students + age of teacher =21x22=462

Age of teacher= 462-440=22 years.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. Q1F, S2E, U6D, W21C, ?

The first letter of each term is moved two steps forward and the last letter is moved one steps backward to obtain the corresponding letters of the next term. The number series runs as follows :

1 x 1 + 1 = 2,

2 x 2 + 2 = 6,

6 x 3 + 3 = 21,

21 x 4 + 4 = 88.

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What is the unit digit in(795 - 358)?

Unit digit in 795 = Unit digit in [(74)23 x 73]

= Unit digit in [(Unit digit in(2401))23 x (343)]

= Unit digit in (123 x 343)

= Unit digit in (343)

= 3

Unit digit in 358 = Unit digit in [(34)14 x 32]

= Unit digit in [Unit digit in (81)14 x 32]

= Unit digit in [(1)14 x 32]

= Unit digit in (1 x 9)

= Unit digit in (9)

= 9

Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.

So, Option B is the answer.

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The sum of all two digit numbers divisible by 5 is

Required numbers are 10, 15, 20, 25, ..., 95

This is an A.P. in which a = 10, d = 5 and l = 95.

tn = 95 a + (n - 1)d = 95

10 + (n - 1) x 5 = 95

(n - 1) x 5 = 85

(n - 1) = 17

n = 18

Required Sum =n/2(a + l)=18/2x (10 + 95) = (9 x 105) = 945.

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