. In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. LXF, MTJ, NPN, OLR, ?

The first letter of each term is moved one step forward, the second letter is moved four steps backward and the third letter is moved four steps forward to obtain the corresponding letters of the next term.

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In following question, a number series is given with one term missing. Choose correct alternative

1, 2, 3, 6, 9, 18, x , 54

1, 2, 3, 6, 9, 18, x , 54

The numbers are alternatively multiplied by 2 and 3/2.

So, 1 X 2 = 2, 2 X 3/2 = 3,

3 X 2 = 6, 6 X 3/2 = 9,

so missing number = 18 X 3/2 = 27.

In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. J2Z, K4X, 17V, ?, H16R, M22P

The first letters in odd numbered terms from series J, I, H and in even numbered terms from the series K, L, M. The sequence followed by the numbers is + 2, + 3, + 4, + 5, + 6. The third letter of each term is moved two steps backward to obtain the third letter of the next term.

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In following alphabet series , one term missing as shown by question mark . Choose missing term from options.

Z, L, X, J, V, H, T, F, ?, ?

The given sequence consists of two series -- Z, X, V, T, ? and L, J, H, F, ?, both consisting of alternate letters in a reverse order.

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Look at this series: 21, 9, 21, 11, 21, 13, . . .

What number should come next?

What number should come next?

In this alternating repetition series, the random number 21 is interpolated every other number into an otherwise simple addition series that increases by 2, beginning with the number 9.

In this Series 21 is common random number.

Now add 2 with 9.

9 + 2 = 11

21 is next common number.

11 + 2 = 13

21 is next common number.

13 + 2 = 15.

21 is next common number.

So the answer is 21..

Which one of the following is a prime number ?

551 > 22

All prime numbers less than 24 are : 2, 3, 5, 7, 11, 13, 17, 19, 23.

119 is divisible by 7; 187 is divisible by 11; 247 is divisible by 13 and 551 is divisible by 19.

So, none of the given numbers is prime.

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A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:

4 | x z = 6 x 1 + 4 = 10

5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53

6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214

| 1 - 4

Hence, required number = 214.

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P is the brother of D. X is the sister of P. A is the brother of F. F is the daughter of D. M is the father of X. Who is the uncle of A?

A is the brother of F who is the daughter of D.So, A is the son of D.P is the brother of D . So, P is the uncle of A..

In alphabet series, some alphabets are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

_ c _ bd _ cdcda _ a _ db _ a

The series is acdb / dacb / cdab / acdb / da. The third letter in each sequence becomes the first letter in the following sequence..