The average of six consecutive odd numbers is 61. What is the difference between the highest and lowest numbers:

Let's 6 consecutive odd numbers are:

3,5,7,9,11,13

Lowest term is 3 and highest is 13

13-3=10

So difference of 10 will remain the same in the consecutive series numbers.

In following questions, one term in number series is incorrect.

Find out the incorrect number

3, 2, 8, 9, 13, 22, 18, 32, 23, 42

Find out the incorrect number

3, 2, 8, 9, 13, 22, 18, 32, 23, 42

The given sequence is a combination of two series:

I. 3, 8, 13, 18, 23 and

II 2, 9, 22, 32,42

The pattern in I is + 5 and the pattern in II is + 10.

So, in II, 9 is wrong and must be replaced by (2 + 10) i.e. 12.

A family consists of six members P, Q, R, X, Y and Z. Q is the son of R but R is not mother of Q. P and R are a married couple. Y is the brother of R. X is the daughter of P. Z is the brother of P. Which is a pair of brothers?

Option (D)

Q is the son of R but R is not the mother. So, R is the father of Q. P is married to R. So, P is the wife of R and the mother of Q. X is the daughter of P and hence of R and so she is the sister of Q. Y is the brother of R and Z is the brother of P.

Clearly, Y is brother of R who is a male. So, Y and R is a pair of brothers.

In alphabet series, some alphabets are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

abca _ bcaab _ aa _ caa _ c

The series is a / bcaa / bcaa / bcaa / bcaa / bc. Thus, the pattern bcaa is repeated.

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A is the brother of B. B is the brother of C. D is the father of A. Based on these three statements, which of the following statement cannot be definitely true?

Option (D)

A is the brother of B and B is the brother of C. So, C may be the brother or sister of A.

A + B means A is the daughter of B ;

A x B means A is the son of B and

A - B means A is the wife of B.

If P x Q - S, which of the following is true?

Option (B)

P x Q - S means P is the son of Q who is the wife of S i.e. P is the son of S or S is the father of P.

The ratio of Two Sisters Alice and Betty is 3/2. However if the age of Alice before 15 years and that of Betty after 15 years than the original ratio is reserved. What is the age of Betty?

Let

Alice age's= A and Betty Age's=B

Given that

A / b = 3 / 2

2 A= 3 B

2A-3B=0.......(1)

And also given that

(A -15 )/ (B+ 15 )= 2 / 3

3 A- 45 =2B-30

3A - 2B = 75..... (2)

By solving both equation

B=30

So Batty is 30 years old

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. Q1F, S2E, U6D, W21C, ?

The first letter of each term is moved two steps forward and the last letter is moved one steps backward to obtain the corresponding letters of the next term. The number series runs as follows :

1 x 1 + 1 = 2,

2 x 2 + 2 = 6,

6 x 3 + 3 = 21,

21 x 4 + 4 = 88.

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In a family , there are six members A,B,C,D,E, and F. A and B are married couples. A being the male member. D is the only son of C, who is the brother of A. E is the sister of D. B is daughter in law of F, whose husband has died. h ow many male members are there in the family?

A is male.B the wife is female. C, the brother is male. D the son is male.E is the sister is female . F the mother is female. so, there are three male members.

The temperature in 0 F on 20 days during the month of June

was as follows:

70 F, 76 F, 76 F, 74 F, 70 F, 70 F, 72 F, 74 F, 80 F,

74F,74F,78F,76F,78 F,76F,74F,78F,80F,76F

What is the mode of the temperature for the month of June?

76 and 78 is the highest occurrence in series..

A person Travels 50 km per hour. If we increase his speed by 10 km per hour, how many minutes will it take to cover 7500 m.

Speed= 50 km per hour

If the speed is increased by 10 kilometre per hour

Then the new speed= 60 km per hour

So distance covered in 1 hour=60 km/ hr

Then the distance covered in 60 minute= 60000

Distance covered in 1 minute=1000m

The new speed 1000 per minute=1000 m /min

Distance to be covered 7500 m= 7500 meters.

Time=7500/1000=7.5 min

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