5 Minutes Test
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Question No 2
Ten years ago Akram was thrice as old as Aslam was, but 10 years hence, he will be only twice as old. What is Akram's present age?
Select the correct answer
Solution!
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Question No 6
Bill's age is 1/3 of Mike's age, who is 60% of James' age. Tom is twice as old as Mike. What is the ratio of Bill's age to Tom's age?
Select the correct answer
Solution!
Let Bill's age is Z, Mike's age is Y and Tom's age is X.
Given that
Z = (1/3)Y
and
Y = (60/100)X
Y = (6/10)X
Tom's Age is double of Mike's age mean his age is 2y.
Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is
[(1/3)Y] / 2Y
(1/3)*(1/2) = 1/6
Hence ratio between Bill's and Tom's age is 1/6..
Let Bill's age is Z, Mike's age is Y and Tom's age is X.
Given that
Z = (1/3)Y
and
Y = (60/100)X
Y = (6/10)X
Tom's Age is double of Mike's age mean his age is 2y.
Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is
[(1/3)Y] / 2Y
(1/3)*(1/2) = 1/6
Hence ratio between Bill's and Tom's age is 1/6..
Question No 9
At 3:40, the hour hand and the minute hand of a clock form an angle of ...
Select the correct answer
Solution!
Angle traced by hour hand in 12 hrs = 360 degree
Angle traced by it in 11/3 hrs = (360/12 * 11/3) = 110 degree
Angle traced by minute hand in 60 min. = 360 degree
Angle traced by it in 40 min = (360/60 * 40) = 240 degree
So, Required angle (240 - 110) = 130 degree.
Angle traced by hour hand in 12 hrs = 360 degree
Angle traced by it in 11/3 hrs = (360/12 * 11/3) = 110 degree
Angle traced by minute hand in 60 min. = 360 degree
Angle traced by it in 40 min = (360/60 * 40) = 240 degree
So, Required angle (240 - 110) = 130 degree.
Question No 12
A can do a certain work in the same time in which B and C together can do it.If A and B together could do it in 10 days and C alone in 50 days,then B alone could do it in
Select the correct answer
Solution!
(A + B)'s 1 day's work = 1/10
C's 1 day's work = 1/50
(A + B + C)'s 1 day's work = (1/10 + 1/50) = 6/50 = 3/25...(1)
A's 1 day's work = (B + C)'s 1 day's work .... (2)
From (1) and (2), we get
2 * (A's 1 day's work) = 3/25
A's 1 day's work = 3/50
So, B's 1 day's work (1/10 - 3/50) = 2/50 = 1/25
Hence, B alone could do the work in 25 days..
(A + B)'s 1 day's work = 1/10
C's 1 day's work = 1/50
(A + B + C)'s 1 day's work = (1/10 + 1/50) = 6/50 = 3/25...(1)
A's 1 day's work = (B + C)'s 1 day's work .... (2)
From (1) and (2), we get
2 * (A's 1 day's work) = 3/25
A's 1 day's work = 3/50
So, B's 1 day's work (1/10 - 3/50) = 2/50 = 1/25
Hence, B alone could do the work in 25 days..
Question No 14
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Select the correct answer
Solution!
Let the length of the train be x metres and its speed by y m/sec.
Then,
x/y = 8
x = 8y
Now, (x+264)/20 = y
8y + 264 = 20y
y = 22
Hence, Speed = 22 m/sec
= 22 * (18/5)
= 79.2 km/hr.
Let the length of the train be x metres and its speed by y m/sec.
Then,
x/y = 8
x = 8y
Now, (x+264)/20 = y
8y + 264 = 20y
y = 22
Hence, Speed = 22 m/sec
= 22 * (18/5)
= 79.2 km/hr.