5 Minutes Test
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Test Report
Question No 1
Choose the word that is a necessary part of the word "guitar"
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Solution!
A guitar does not exist without strings, so strings are an essential part of a guitar. A band is not necessary to a guitar (choice a). Guitar playing can be learned without a teacher (choice b). Songs are byproducts of a guitar (choice c)..
A guitar does not exist without strings, so strings are an essential part of a guitar. A band is not necessary to a guitar (choice a). Guitar playing can be learned without a teacher (choice b). Songs are byproducts of a guitar (choice c)..
Question No 3
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is
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Solution!
Let!C.P. of each article be Re. 1 C.P. of x articles = Rs. x.! !S.P. of x articles = Rs. 20.! !Profit = Rs. (20 - x)! !So, (20-x)/x * 100 = 25!2000 - 100x = 25x!125x = 2000! !Hence, x = 16.
Let!C.P. of each article be Re. 1 C.P. of x articles = Rs. x.! !S.P. of x articles = Rs. 20.! !Profit = Rs. (20 - x)! !So, (20-x)/x * 100 = 25!2000 - 100x = 25x!125x = 2000! !Hence, x = 16.
Question No 4
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is
Select the correct answer
Solution!
Let the speed of the second train be x km/hr.! !Relative speed = (x + 50) km/hr!= (x+50)*(5/18) m/s!= (250+5x)18 m/s! !Distance covered = (108 + 112) = 220 m! !So, 220/[(250 + 5x) /18] = 6!250 + 5x = 660! !Hence, x = 82 km/hr.
Let the speed of the second train be x km/hr.! !Relative speed = (x + 50) km/hr!= (x+50)*(5/18) m/s!= (250+5x)18 m/s! !Distance covered = (108 + 112) = 220 m! !So, 220/[(250 + 5x) /18] = 6!250 + 5x = 660! !Hence, x = 82 km/hr.
Question No 5
Meena is thrice as old as Sheraz. Fatima will be twice as old as Meena 6 years hence. Six years ago Sheraz was five years old. What is Fatima's present age?
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Solution!
Let present age of Sheraz is x and present age of Fatima is y.! !So,!Meena's age = 3x! !Given that!y+6 = 2(3x+6) ...(1)!and!x-6 = 5!x = 11! !Put value of x in equation(1)! !y+6 = 2(33+6)!y+6 = 78!y = 72! !Hence Fatima's present age is 72 years..
Let present age of Sheraz is x and present age of Fatima is y.! !So,!Meena's age = 3x! !Given that!y+6 = 2(3x+6) ...(1)!and!x-6 = 5!x = 11! !Put value of x in equation(1)! !y+6 = 2(33+6)!y+6 = 78!y = 72! !Hence Fatima's present age is 72 years..
Question No 6
Pointing to a girl Sandeep said, "She is the daughter of the only sister of my father." How is sandeep related to the girl?
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Solution!
The girl is the daughter of the sister of Sandeep's father.! !Hence, the girl is the cousin or Sandeep is the cousin of the girl..
The girl is the daughter of the sister of Sandeep's father.! !Hence, the girl is the cousin or Sandeep is the cousin of the girl..
Question No 7
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is
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Solution!
Ratio of times taken by Sakshi and Tanya = 125/100 = 5/4! !Suppose Tanya takes x days to do the work.! !5/4 = 20/x!x = (4*20)/5! !x = 16 days.! !Hence, Tanya takes 16 days to complete the work..
Ratio of times taken by Sakshi and Tanya = 125/100 = 5/4! !Suppose Tanya takes x days to do the work.! !5/4 = 20/x!x = (4*20)/5! !x = 16 days.! !Hence, Tanya takes 16 days to complete the work..
Question No 10
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?
Select the correct answer
Solution!
Let the age of the youngest child = x! !Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12).! !Then,!X + (x+3) + (x+6) + (x+9) + (x+12) = 50!5x + 30 =50!5x = 20!x = 20/5 = 4.
Let the age of the youngest child = x! !Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12).! !Then,!X + (x+3) + (x+6) + (x+9) + (x+12) = 50!5x + 30 =50!5x = 20!x = 20/5 = 4.
Question No 11
A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is
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Solution!
Let the speed of the stream x mph.! !Then,!Speed downstream = (10 + x) mph! !Speed upstream = (10 - x) mph! !So, [36/(10 - x)] - [36/(10 + x)] = 90/60!(72x)*60 = 90 (100 - x*x)!(x+ 50)(x - 2) = 0! !Hence, x = 2 mph..
Let the speed of the stream x mph.! !Then,!Speed downstream = (10 + x) mph! !Speed upstream = (10 - x) mph! !So, [36/(10 - x)] - [36/(10 + x)] = 90/60!(72x)*60 = 90 (100 - x*x)!(x+ 50)(x - 2) = 0! !Hence, x = 2 mph..
Question No 13
The day that will come two days after tomorrow will be Thursday. What was the day that Dawned two days before yesterday.
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Solution!
As the day, two days after tomorrow is Thursday so tomorrow is Tuesday and today is Monday and yesterday was Sunday. Hence the day two days before yesterday was Friday..
As the day, two days after tomorrow is Thursday so tomorrow is Tuesday and today is Monday and yesterday was Sunday. Hence the day two days before yesterday was Friday..
