5 Minutes Test
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Question No 1
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
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Solution!
Formula for converting from km/hr to m/s is!X km/hr = x * (5/18)m/s! !Therefore,!Speed = 45 * (5/18) = 25/2 m/s! !Total distance to be covered = (360 + 140) m = 500 m! !Formula for finding Time = (Distance/Speed)! !Hence, Required time = (500*2)/25!= 40 seconds.
Formula for converting from km/hr to m/s is!X km/hr = x * (5/18)m/s! !Therefore,!Speed = 45 * (5/18) = 25/2 m/s! !Total distance to be covered = (360 + 140) m = 500 m! !Formula for finding Time = (Distance/Speed)! !Hence, Required time = (500*2)/25!= 40 seconds.
Question No 4
A 150m long train is running at the speed of 36km/h. In what time will it pass the 80m long bridge?
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Solution!
Length of train = L1 = 150m!Speed = v = 36 Km/h = 36*(5/18) = 10 m/s!Length of bridge = L2 = 80m! !Time = t = (L1 + L2)/v!t = (150+80)/10 = 23! !Hence the train will pass the 80 meter long bridge in 23 seconds..
Length of train = L1 = 150m!Speed = v = 36 Km/h = 36*(5/18) = 10 m/s!Length of bridge = L2 = 80m! !Time = t = (L1 + L2)/v!t = (150+80)/10 = 23! !Hence the train will pass the 80 meter long bridge in 23 seconds..
Question No 5
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
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Solution!
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years!= 4x years.! !(4x + 8) = 5/2 (x+8)!8x + 16 = 5x + 40!3x = 24!x = 8! !Hence, required ratio = (4x+16)/(x+160)!= 48/24 = 2.
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years!= 4x years.! !(4x + 8) = 5/2 (x+8)!8x + 16 = 5x + 40!3x = 24!x = 8! !Hence, required ratio = (4x+16)/(x+160)!= 48/24 = 2.
Question No 7
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?
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Solution!
Let the age of the youngest child = x! !Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12).! !Then,!X + (x+3) + (x+6) + (x+9) + (x+12) = 50!5x + 30 =50!5x = 20!x = 20/5 = 4.
Let the age of the youngest child = x! !Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12).! !Then,!X + (x+3) + (x+6) + (x+9) + (x+12) = 50!5x + 30 =50!5x = 20!x = 20/5 = 4.
Question No 13
If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A x B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?
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Solution!
P - M = P is the brother of M! !M + N = M is the mother of N! !N x Q = N is the sister of Q! !Therefore, P is the maternal uncle of Q..
P - M = P is the brother of M! !M + N = M is the mother of N! !N x Q = N is the sister of Q! !Therefore, P is the maternal uncle of Q..
Question No 14
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
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Solution!
Let, 1 man's 1 day's work = x!and!1 woman's 1 day's work = y! !Then, 4x + 6y = 1/8 nd 3x + 7y = 1/10! !Solving the two equations, we get!x = 11/400!y = 1/400! !So, One woman's 1 day's work = 1/400! !10 women's 1 day's work = (1/400 * 10) = 1/40! !Hence, 10 women will complete the work in 40 days..
Let, 1 man's 1 day's work = x!and!1 woman's 1 day's work = y! !Then, 4x + 6y = 1/8 nd 3x + 7y = 1/10! !Solving the two equations, we get!x = 11/400!y = 1/400! !So, One woman's 1 day's work = 1/400! !10 women's 1 day's work = (1/400 * 10) = 1/40! !Hence, 10 women will complete the work in 40 days..
