10 Minutes Test
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Total Questions:
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Test Report
Question No 6
The ratio of A's age and B's age is 3/7, and the difference of their ages is 16 years. Find the age of B.
Select the correct answer
Solution!
Given that
A/B = 3/7 ...(1)
and
B-A = 16 ...(2)
Put value of A from equation(1) in equation(2)
B-(3/7)B = 16
(7B-3B)/7 = 16
4B = 112
B = 28
Hence Age of B is 28 years..
Given that
A/B = 3/7 ...(1)
and
B-A = 16 ...(2)
Put value of A from equation(1) in equation(2)
B-(3/7)B = 16
(7B-3B)/7 = 16
4B = 112
B = 28
Hence Age of B is 28 years..
Question No 7
A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B?
Select the correct answer
Solution!
Let the age of C = x.
Then
Age of B = 2x
Age of A = 2 + 2x
The total age of A,B and C =27
(2+2x) + 2x + x = 27
5x = 25
B's age = 2x = 2 * 5 = 10.
Let the age of C = x.
Then
Age of B = 2x
Age of A = 2 + 2x
The total age of A,B and C =27
(2+2x) + 2x + x = 27
5x = 25
B's age = 2x = 2 * 5 = 10.
Question No 10
Bill's age is 1/3 of Mike's age, who is 60% of James' age. Tom is twice as old as Mike. What is the ratio of Bill's age to Tom's age?
Select the correct answer
Solution!
Let Bill's age is Z, Mike's age is Y and Tom's age is X.
Given that
Z = (1/3)Y
and
Y = (60/100)X
Y = (6/10)X
Tom's Age is double of Mike's age mean his age is 2y.
Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is
[(1/3)Y] / 2Y
(1/3)*(1/2) = 1/6
Hence ratio between Bill's and Tom's age is 1/6..
Let Bill's age is Z, Mike's age is Y and Tom's age is X.
Given that
Z = (1/3)Y
and
Y = (60/100)X
Y = (6/10)X
Tom's Age is double of Mike's age mean his age is 2y.
Now Bill's age is (1/3)Y and Tom's age is 2Y and ratio between them is
[(1/3)Y] / 2Y
(1/3)*(1/2) = 1/6
Hence ratio between Bill's and Tom's age is 1/6..
Question No 17
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is
Select the correct answer
Solution!
Let the speed of the stream be x km/hr.
Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 - x) km/hr
So, [30/(15 + x)] + [30/(15 - x)] = 9/2
900/(225 - x*x) = 9/2
x = 5 km/hr.
Let the speed of the stream be x km/hr.
Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 - x) km/hr
So, [30/(15 + x)] + [30/(15 - x)] = 9/2
900/(225 - x*x) = 9/2
x = 5 km/hr.
Question No 19
Pointing to a lady a person said, "The son of her only brother is the brother of my wife." How is the lady related to the person?
Select the correct answer
Solution!
Brother of person's wife is brother-in-law of the person.
Hence, the son of lady's brother is brother-in-law of the person.
Therefore, the brother of the lady is the father-in-law of the person. Hence, the lady is the sister of the person's father-in-law..
Brother of person's wife is brother-in-law of the person.
Hence, the son of lady's brother is brother-in-law of the person.
Therefore, the brother of the lady is the father-in-law of the person. Hence, the lady is the sister of the person's father-in-law..
Question No 20
An estate agent sold a property at a profit of 10% for $825000. What was cost price of the property?
Select the correct answer
Solution!
Let cost price of the property is x.
10% of x = 10x/100 = x/10
Now
825000 - (x/10) = x
8250000 - x = 10x
8250000 = 11x
x = 750000
Hence cost price of the property is $750000..
Let cost price of the property is x.
10% of x = 10x/100 = x/10
Now
825000 - (x/10) = x
8250000 - x = 10x
8250000 = 11x
x = 750000
Hence cost price of the property is $750000..
Question No 23
What is the angle between the hands of a clock at 8:50 am?
Select the correct answer
Solution!
At 8:50 hour hand is nearly at 8
Minute hand is at 10
Angle between 8 and 10 is 60 degree.
Hour hand move 1/2 degree in one minute.
In 50 Minutes hour hand will move 1/2 * 50 = 25 degree
Hence, Angle between hands is 60 - 25 = 35 degree.
At 8:50 hour hand is nearly at 8
Minute hand is at 10
Angle between 8 and 10 is 60 degree.
Hour hand move 1/2 degree in one minute.
In 50 Minutes hour hand will move 1/2 * 50 = 25 degree
Hence, Angle between hands is 60 - 25 = 35 degree.
Question No 27
David can swim at the speed of 30 km/h in still water and speed of water is 4 km/h. What is his speed of swimming against the direction of water?
Select the correct answer
Solution!
David's speed in still water = u = 30 Km/h
Speed of water = v = 4 Km/h
David's swimming speed against water = u-v = 30-4 = 26 Km/h.
David's speed in still water = u = 30 Km/h
Speed of water = v = 4 Km/h
David's swimming speed against water = u-v = 30-4 = 26 Km/h.
Question No 28
A is thrice as good as a workman as B and therefore is able to finish a job in 60 days less than B.Working together,they can do it in
Select the correct answer
Solution!
Ratio of times taken by A and B = 1/3
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes (3/2 * 60) = 90 days
So, A takes 30 days to do the work.
A's 1 day's work = 1/30
B's 1 day's work = 1/90
(A + B)'s 1 day's work = (1/30 + 1/90) = 4/90 = 2/45
Hence, A and B together can do the work in 45/2 = 22.5 days.
Ratio of times taken by A and B = 1/3
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes (3/2 * 60) = 90 days
So, A takes 30 days to do the work.
A's 1 day's work = 1/30
B's 1 day's work = 1/90
(A + B)'s 1 day's work = (1/30 + 1/90) = 4/90 = 2/45
Hence, A and B together can do the work in 45/2 = 22.5 days.
Question No 30
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is
Select the correct answer
Solution!
Speed of the train relative to man = (125/10) m/s
= (25/2)m/s
= (25/2) * (18/5)km/hr
= 45 km/hr
Let the speed of the train be x km/hr.
Then,
relative speed = (x - 5) km/hr
x - 5 = 45
Hence, x = 50 km/hr.
Speed of the train relative to man = (125/10) m/s
= (25/2)m/s
= (25/2) * (18/5)km/hr
= 45 km/hr
Let the speed of the train be x km/hr.
Then,
relative speed = (x - 5) km/hr
x - 5 = 45
Hence, x = 50 km/hr.