10 Minutes Test
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Result
Total Questions:
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Wrong:
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Test Report
Question No 3
What is the angle between the hands of a clock at 8:50 am?
Select the correct answer
Solution!
At 8:50 hour hand is nearly at 8
Minute hand is at 10
Angle between 8 and 10 is 60 degree.
Hour hand move 1/2 degree in one minute.
In 50 Minutes hour hand will move 1/2 * 50 = 25 degree
Hence, Angle between hands is 60 - 25 = 35 degree.
At 8:50 hour hand is nearly at 8
Minute hand is at 10
Angle between 8 and 10 is 60 degree.
Hour hand move 1/2 degree in one minute.
In 50 Minutes hour hand will move 1/2 * 50 = 25 degree
Hence, Angle between hands is 60 - 25 = 35 degree.
Question No 5
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Select the correct answer
Solution!
Relative speed = (120 + 80) km/hr
= 200(5/18)m/s
= (500/9)m/s
Let the length of the other train be x metres
Then,
(x+270)/9 = 500/9
x + 270 = 500
Hence, x = 230.
Relative speed = (120 + 80) km/hr
= 200(5/18)m/s
= (500/9)m/s
Let the length of the other train be x metres
Then,
(x+270)/9 = 500/9
x + 270 = 500
Hence, x = 230.
Question No 6
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is
Select the correct answer
Solution!
Let
C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x)
So, (20-x)/x * 100 = 25
2000 - 100x = 25x
125x = 2000
Hence, x = 16.
Let
C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x)
So, (20-x)/x * 100 = 25
2000 - 100x = 25x
125x = 2000
Hence, x = 16.
Question No 7
At present, the ratio between the ages of Arun and Deepak is 4/3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?
Select the correct answer
Solution!
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.
Then,
4x + 6 = 26
4x = 20
x = 5
Hence, Deepak's age = 3x = 15 years..
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.
Then,
4x + 6 = 26
4x = 20
x = 5
Hence, Deepak's age = 3x = 15 years..
Question No 8
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is
Select the correct answer
Solution!
Let the speed of the stream be x km/hr.
Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 - x) km/hr
So, [30/(15 + x)] + [30/(15 - x)] = 9/2
900/(225 - x*x) = 9/2
x = 5 km/hr.
Let the speed of the stream be x km/hr.
Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 - x) km/hr
So, [30/(15 + x)] + [30/(15 - x)] = 9/2
900/(225 - x*x) = 9/2
x = 5 km/hr.
Question No 11
A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is
Select the correct answer
Solution!
Speed = 78 * (5/18) = 65/3 m/s
Time = 1 minute = 60 seconds
Let the length of the tunnel be x metres
Then,
(800+x)/60 = 65/3
3(800 + x) = 3900
Hence, x = 500.
Speed = 78 * (5/18) = 65/3 m/s
Time = 1 minute = 60 seconds
Let the length of the tunnel be x metres
Then,
(800+x)/60 = 65/3
3(800 + x) = 3900
Hence, x = 500.
Question No 13
The average age of A and B is 20. If C were to replace A, the average would be 19, and if B was replaced by C, the average would be 21. The age of C is
Select the correct answer
Solution!
Given that
(A+B)/2 = 20
A+B = 40 ...(1)
and
(C+B)/2 = 19
C+B = 38 ...(2)
and
(A+C)/2 = 21
A+C = 42 ...(3)
Put value of A from equation(1) in equation(3)
(40-B)+C = 42
C-B = 2 ...(4)
By simultaneously solving equation(2) and equation(4)
C = 20
Hence C is 20 years old..
Given that
(A+B)/2 = 20
A+B = 40 ...(1)
and
(C+B)/2 = 19
C+B = 38 ...(2)
and
(A+C)/2 = 21
A+C = 42 ...(3)
Put value of A from equation(1) in equation(3)
(40-B)+C = 42
C-B = 2 ...(4)
By simultaneously solving equation(2) and equation(4)
C = 20
Hence C is 20 years old..
Question No 17
If A + B means A is the brother of B; A - B means A is the sister of B and A x B means A is the father of B. Which of the following means that C is the son of M?
Select the correct answer
Solution!
M x N = M is the father of N
N - C = N is the sister of C
and C + F = C is the brother of F.
Hence, M is the father of C or C is the son of M..
M x N = M is the father of N
N - C = N is the sister of C
and C + F = C is the brother of F.
Hence, M is the father of C or C is the son of M..
Question No 19
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Select the correct answer
Solution!
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
So, the day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
Hence 6th March, 2004 is Sunday..
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
So, the day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
Hence 6th March, 2004 is Sunday..
Question No 22
Tina is twice as old as David. 15 years ago, Tina's age was 5 times the age of David. What is the present age of Tina?
Select the correct answer
Solution!
Let David's age is x and Tina's age is y.
Given that
y = 2x
y-2x = 0 ...(1)
and also given that
y-15 = 5(x-15)
y-15 = 5x-75
y-5x = -60 ...(2)
By simultaneously solving equation(1) and equation(2)
y = 40
Hence Tina's present age is 40 years..
Let David's age is x and Tina's age is y.
Given that
y = 2x
y-2x = 0 ...(1)
and also given that
y-15 = 5(x-15)
y-15 = 5x-75
y-5x = -60 ...(2)
By simultaneously solving equation(1) and equation(2)
y = 40
Hence Tina's present age is 40 years..
Question No 28
In a fort there is enough food sufficient for 1200 men for 10 days. How long the food would have last for if there would have been 1000 men.
Select the correct answer
Solution!
Let food will last for x days.
As men and days are inversely proportional to each other so
x/10 = 1200/1000
x = 12
Hence food will last for 12 days if there were 1000 men..
Let food will last for x days.
As men and days are inversely proportional to each other so
x/10 = 1200/1000
x = 12
Hence food will last for 12 days if there were 1000 men..