20 Minutes Test
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Test Report
Question No 2
10 women can complete a work in 7 days and 10 children take 14 days to complete the work.How many days will 5 women and 10 children take to complete the work?
Select the correct answer
Solution!
1 woman's 1 day's work =1/70
1 child's 1 day's work =1/140
(5 women + 10 children)'s 1 day's work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7
Hence, 5 women and 10 children will complete the work in 7 days..
1 woman's 1 day's work =1/70
1 child's 1 day's work =1/140
(5 women + 10 children)'s 1 day's work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7
Hence, 5 women and 10 children will complete the work in 7 days..
Question No 7
Anupam said to a lady sitting in a car, "The only daughter of the brother of my wife is the sister-in-law of the brother of your sister." How the husband of the lady is related to Anupam?
Select the correct answer
Solution!
Anupam's son-in-law is the brother of the lady who was sitting in the car. Hence, the husband is also the son-in-law of Anupam..
Anupam's son-in-law is the brother of the lady who was sitting in the car. Hence, the husband is also the son-in-law of Anupam..
Question No 9
A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is
Select the correct answer
Solution!
Speed = 78 * (5/18) = 65/3 m/s
Time = 1 minute = 60 seconds
Let the length of the tunnel be x metres
Then,
(800+x)/60 = 65/3
3(800 + x) = 3900
Hence, x = 500.
Speed = 78 * (5/18) = 65/3 m/s
Time = 1 minute = 60 seconds
Let the length of the tunnel be x metres
Then,
(800+x)/60 = 65/3
3(800 + x) = 3900
Hence, x = 500.
Question No 10
Pointing to a person, Deepak said, "His only brother is the father of my daughter's father". How is the person related to Deepak?
Select the correct answer
Solution!
Father of Deepak's daughter's father = Deepak's father.
Hence, the person in the brother of Deepak's father.
Therefore, the person is the uncle of Deepak..
Father of Deepak's daughter's father = Deepak's father.
Hence, the person in the brother of Deepak's father.
Therefore, the person is the uncle of Deepak..
Question No 11
Price of a mobile phone is Rs. 8,000. A man has enough money to purchase 3 mobiles. How many mobile can he purchase if the price is reduced by Rs. 2000?
Select the correct answer
Solution!
Minimum amount of money that he has = 8,000 * 3 = 24,000
If price is reduced to 6,000, he can purchase 24,000/6,000 = 4.
Minimum amount of money that he has = 8,000 * 3 = 24,000
If price is reduced to 6,000, he can purchase 24,000/6,000 = 4.
Question No 14
Ten years ago Akram was thrice as old as Aslam was, but 10 years hence, he will be only twice as old. What is Akram's present age?
Select the correct answer
Solution!
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Question No 15
A man can row 1 km upstream in 20 minutes, and downstream in 15 minutes. What is the speed of the current?
Select the correct answer
Solution!
20 minutes = 20/60 = 1/3 hours
Upstream distance covered in 1/3 hours = 1 Km
Upstream distance covered in 1 hour = 1/(1/3) = 3 Km
Upstream speed = y = 3 Km/h
Now
15 minutes = 15/60 = 1/4 hours
Downstream distance covered in 1/4 hours = 1 Km
Downstream distance covered in 1 hour = 1/(1/4) = 4 Km
Downstream speed = 4 Km/h
speed of water = (1/2)*(4-3) = 1/2 = 0.5 Km/h.
20 minutes = 20/60 = 1/3 hours
Upstream distance covered in 1/3 hours = 1 Km
Upstream distance covered in 1 hour = 1/(1/3) = 3 Km
Upstream speed = y = 3 Km/h
Now
15 minutes = 15/60 = 1/4 hours
Downstream distance covered in 1/4 hours = 1 Km
Downstream distance covered in 1 hour = 1/(1/4) = 4 Km
Downstream speed = 4 Km/h
speed of water = (1/2)*(4-3) = 1/2 = 0.5 Km/h.
Question No 19
A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Select the correct answer
Solution!
Speed downstream = (13 + 4) km/hr = 17 km/hr
Time taken to travel 68 km downstream = (68/17)hrs
= 4 hours.
Speed downstream = (13 + 4) km/hr = 17 km/hr
Time taken to travel 68 km downstream = (68/17)hrs
= 4 hours.
Question No 21
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Select the correct answer
Solution!
Whole work is done by A in (20 * 5/4) = 25 days
Now, (1 - 4/5) i.e., 1/5 work is done by A and B in 3 days.
Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work = 1/25
(A + B)'s 1 day's work = 1/15
So, B's 1 day's work = (1/15 - 1/25) = 4/150 = 2/75
Hence, B alone would do the work in 75/2 = 37.5 days..
Whole work is done by A in (20 * 5/4) = 25 days
Now, (1 - 4/5) i.e., 1/5 work is done by A and B in 3 days.
Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work = 1/25
(A + B)'s 1 day's work = 1/15
So, B's 1 day's work = (1/15 - 1/25) = 4/150 = 2/75
Hence, B alone would do the work in 75/2 = 37.5 days..
Question No 22
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Select the correct answer
Solution!
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years
= 4x years.
(4x + 8) = 5/2 (x+8)
8x + 16 = 5x + 40
3x = 24
x = 8
Hence, required ratio = (4x+16)/(x+160)
= 48/24 = 2.
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years
= 4x years.
(4x + 8) = 5/2 (x+8)
8x + 16 = 5x + 40
3x = 24
x = 8
Hence, required ratio = (4x+16)/(x+160)
= 48/24 = 2.
Question No 24
The 15th of the month falls on the day preceding Sunday, on what day will the 6th of the month fall?
Select the correct answer
Solution!
As on 15th of the month day is Saturday so on 8th the day will also Saturday. Hence on 6th of the month day will be Thursday(Two days before Saturday)..
As on 15th of the month day is Saturday so on 8th the day will also Saturday. Hence on 6th of the month day will be Thursday(Two days before Saturday)..
Question No 26
X can do a piece of work in 40 days.He works at it for 8 days and then Y finished it in 16 days.How long will they together take to complete the work?
Select the correct answer
Solution!
Work done by X in 8 days = (1/40 * 8)
= 1/5
Remaining work = (1 - 1/5)
4/5
Now, 4/5 work is done by Y in 16 days.
Whole work will be done by Y in (16 * 5/4)
= 20 days
So,
X's 1 day's work = 1/40
Y's 1 day's work = 1/20
(X + Y)'s 1 day's work = (1/40 + 1/20) = 3/40
Hence, X and Y will together complete the work in 40/3 days.
Work done by X in 8 days = (1/40 * 8)
= 1/5
Remaining work = (1 - 1/5)
4/5
Now, 4/5 work is done by Y in 16 days.
Whole work will be done by Y in (16 * 5/4)
= 20 days
So,
X's 1 day's work = 1/40
Y's 1 day's work = 1/20
(X + Y)'s 1 day's work = (1/40 + 1/20) = 3/40
Hence, X and Y will together complete the work in 40/3 days.
Question No 27
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Select the correct answer
Solution!
Relative speed = (120 + 80) km/hr
= 200(5/18)m/s
= (500/9)m/s
Let the length of the other train be x metres
Then,
(x+270)/9 = 500/9
x + 270 = 500
Hence, x = 230.
Relative speed = (120 + 80) km/hr
= 200(5/18)m/s
= (500/9)m/s
Let the length of the other train be x metres
Then,
(x+270)/9 = 500/9
x + 270 = 500
Hence, x = 230.
Question No 29
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, what was the son's age five years back?
Select the correct answer
Solution!
Let the son's present age be x years.
Then
(38 - x) = x
2x = 38
x = 38/2 = 19
Son's age 5 years back = 19-5 = 14 years.
Let the son's present age be x years.
Then
(38 - x) = x
2x = 38
x = 38/2 = 19
Son's age 5 years back = 19-5 = 14 years.
Question No 31
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is
Select the correct answer
Solution!
Speed of the train relative to man = (125/10) m/s
= (25/2)m/s
= (25/2) * (18/5)km/hr
= 45 km/hr
Let the speed of the train be x km/hr.
Then,
relative speed = (x - 5) km/hr
x - 5 = 45
Hence, x = 50 km/hr.
Speed of the train relative to man = (125/10) m/s
= (25/2)m/s
= (25/2) * (18/5)km/hr
= 45 km/hr
Let the speed of the train be x km/hr.
Then,
relative speed = (x - 5) km/hr
x - 5 = 45
Hence, x = 50 km/hr.
Question No 32
A train travelling at the speed of 10m/s can cross a bridge in 23 seconds. If length of the train is 120 meters. What is length of the bridge?
Select the correct answer
Solution!
Speed = v = 10m/s
Time = t = 23s
Length of train = L1 = 120m
Length of bridge = L2 = ?
t = (L1+L2)/v
By putting values
23 = (120+L2)/10
L2 = 230 - 120 = 110m
Hence bridge is 110m long..
Speed = v = 10m/s
Time = t = 23s
Length of train = L1 = 120m
Length of bridge = L2 = ?
t = (L1+L2)/v
By putting values
23 = (120+L2)/10
L2 = 230 - 120 = 110m
Hence bridge is 110m long..
Question No 35
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
Select the correct answer
Solution!
Let the mother's present age be x years.
Then,
the person's present age = (2/5)x years.
(2/5)x + 8 = (1/2)(x + 8)
2(2x + 40) = 5(x + 8)
x = 40
.
Let the mother's present age be x years.
Then,
the person's present age = (2/5)x years.
(2/5)x + 8 = (1/2)(x + 8)
2(2x + 40) = 5(x + 8)
x = 40
.
Question No 38
Veena who is the sister-in-law of Ashok, is the daughter-in-law of Kalyani. Dheeraj is the father of Sudeep who is the only brother of Ashok. How Kalyani is related to Ashok?
Select the correct answer
Solution!
Ashok is the only brother of Sudeep and Veena is the sister-in-law of Ashok.
Hence Veena is the wife of Sudeep.
Kalyani is the mother-in-law of Veena.
Kalyani is the mother of Ashok..
Ashok is the only brother of Sudeep and Veena is the sister-in-law of Ashok.
Hence Veena is the wife of Sudeep.
Kalyani is the mother-in-law of Veena.
Kalyani is the mother of Ashok..
Question No 42
At present, the ratio between the ages of Arun and Deepak is 4/3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?
Select the correct answer
Solution!
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.
Then,
4x + 6 = 26
4x = 20
x = 5
Hence, Deepak's age = 3x = 15 years..
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.
Then,
4x + 6 = 26
4x = 20
x = 5
Hence, Deepak's age = 3x = 15 years..
Question No 50
David can swim at the speed of 30 km/h in still water and speed of water is 4 km/h. What is his speed of swimming against the direction of water?
Select the correct answer
Solution!
David's speed in still water = u = 30 Km/h
Speed of water = v = 4 Km/h
David's swimming speed against water = u-v = 30-4 = 26 Km/h.
David's speed in still water = u = 30 Km/h
Speed of water = v = 4 Km/h
David's swimming speed against water = u-v = 30-4 = 26 Km/h.
Question No 56
A father is 15 times as old as his son. however, 18 years later, he will be only thrice as old as the son. What is the father's present age?
Select the correct answer
Solution!
Let present age of the son is x and present age of Father is y.
Given that
y = 15x
15x-y = 0 ...(1)
and also given that
y+18 = 3(x+18)
y+18 = 3x+54
y-3x = 36 ...(2)
By simultaneously solving equation(1) and equation(2)
y = 45
Hence father's present age is 45 years..
Let present age of the son is x and present age of Father is y.
Given that
y = 15x
15x-y = 0 ...(1)
and also given that
y+18 = 3(x+18)
y+18 = 3x+54
y-3x = 36 ...(2)
By simultaneously solving equation(1) and equation(2)
y = 45
Hence father's present age is 45 years..
Question No 58
A and B can do a job together in 7 days. A is 7/4 times as efficient as B.The same job can be done by A alone in
Select the correct answer
Solution!
(A's 1 day's work) / (B's 1 day's work) = 7/4
Let A's and B's 1 day's work be 7x and 4x respectively.
Then,
7x + 4x = 1/7
11x = 1/7
x = 1/77
Hence, A's 1 day's work = (1/77 * 7) = 1/11.
(A's 1 day's work) / (B's 1 day's work) = 7/4
Let A's and B's 1 day's work be 7x and 4x respectively.
Then,
7x + 4x = 1/7
11x = 1/7
x = 1/77
Hence, A's 1 day's work = (1/77 * 7) = 1/11.
Question No 60
If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A x B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?
Select the correct answer
Solution!
P - M = P is the brother of M
M + N = M is the mother of N
N x Q = N is the sister of Q
Therefore, P is the maternal uncle of Q..
P - M = P is the brother of M
M + N = M is the mother of N
N x Q = N is the sister of Q
Therefore, P is the maternal uncle of Q..