20 Minutes Test
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Test Report
Question No 8
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?
Select the correct answer
Solution!
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then,
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4
Hence, Age of the youngest child = x = 4 years.
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then,
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4
Hence, Age of the youngest child = x = 4 years.
Question No 9
A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Select the correct answer
Solution!
Speed downstream = (13 + 4) km/hr = 17 km/hr
Time taken to travel 68 km downstream = (68/17)hrs
= 4 hours.
Speed downstream = (13 + 4) km/hr = 17 km/hr
Time taken to travel 68 km downstream = (68/17)hrs
= 4 hours.
Question No 10
A man was accompanying a girl, on being asked who the girl was the man said, "Her father was the only son of my father". What was the girl to man?
Select the correct answer
Solution!
If I am a boy and I am only son of my father it means I am talking about myself.
Same is the case here man is father of the girl..
If I am a boy and I am only son of my father it means I am talking about myself.
Same is the case here man is father of the girl..
Question No 12
A 100 meters long train can cross a 150 meters long bridge in 20 seconds. What is the speed of the train?
Select the correct answer
Solution!
Length of the train = L1 = 100m
Length of the bridge = L2 = 150m
Time = t = 20s
Speed = v = ?
v = (L1+L2)/t
By putting values
v = (100+150)/20
v = 250/20 = 12.5m/s
Hence speed of train is 12.5m/s..
Length of the train = L1 = 100m
Length of the bridge = L2 = 150m
Time = t = 20s
Speed = v = ?
v = (L1+L2)/t
By putting values
v = (100+150)/20
v = 250/20 = 12.5m/s
Hence speed of train is 12.5m/s..
Question No 14
A group of workers can do a piece of work in 24 days. However as 7 of them were absent it took 30 days to complete the work. How many people actually worked on the job to complete it?
Select the correct answer
Solution!
Let x workers are required to complete the job.
As workers and days are inversely proportional to each other so
(x-7)/x = 24/30
30x - 210 = 24x
6x = 210
x = 35
Hence 35 workers are required to complete the job in time..
Let x workers are required to complete the job.
As workers and days are inversely proportional to each other so
(x-7)/x = 24/30
30x - 210 = 24x
6x = 210
x = 35
Hence 35 workers are required to complete the job in time..
Question No 16
If A $ B means A is the brother of B; B * C means B is the son of C; C / D means C is the wife of D and A # D means A is the son of D, how C is related to A?
Select the correct answer
Solution!
A $ B = A is the brother of B
B * C = B is the son of C
Hence, A is the son of C
C / D = C is the wife of D
Hence, C is the mother of A..
A $ B = A is the brother of B
B * C = B is the son of C
Hence, A is the son of C
C / D = C is the wife of D
Hence, C is the mother of A..
Question No 17
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Select the correct answer
Solution!
Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr = 60 * (5/18)m/s
= (50/3)m/s
Hence, Time taken to pass the man
= 500 * (3/50)s
= 30 seconds.
Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr = 60 * (5/18)m/s
= (50/3)m/s
Hence, Time taken to pass the man
= 500 * (3/50)s
= 30 seconds.
Question No 19
In 1975, A was thrice as old as B but in 1979, A was only twice as old as B was. How old was A in 1985?
Select the correct answer
Solution!
Let A's age in 1985 was X.
Given that
X-10 = 3(B-10)
X-10 = 3B-30
3B-X = 20 ...(1)
and
X-6 = 2(B-6)
X-6 = 2B-12
2B-X = 6 ...(2)
By simultaneously solving equation(1) and (2) we have
X = 22
Hence A's age in 1985 was 22 years..
Let A's age in 1985 was X.
Given that
X-10 = 3(B-10)
X-10 = 3B-30
3B-X = 20 ...(1)
and
X-6 = 2(B-6)
X-6 = 2B-12
2B-X = 6 ...(2)
By simultaneously solving equation(1) and (2) we have
X = 22
Hence A's age in 1985 was 22 years..
Question No 21
Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7/9, how old is Sachin?
Select the correct answer
Solution!
Let Rahul's age be x years.
Then,
Sachin's age = (x - 7) years.
(x-7)/x = 7/9
9x - 63 = 7x
2x = 63
x = 31.5
Hence, Sachin's age =(x - 7)= 24.5 years.
Let Rahul's age be x years.
Then,
Sachin's age = (x - 7) years.
(x-7)/x = 7/9
9x - 63 = 7x
2x = 63
x = 31.5
Hence, Sachin's age =(x - 7)= 24.5 years.
Question No 23
Ten years ago Akram was thrice as old as Aslam was, but 10 years hence, he will be only twice as old. What is Akram's present age?
Select the correct answer
Solution!
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Let Aslam's present age is x and Akram's present age is y.
Given that
y-10 = 3(x-10)
y-10 = 3x-30
y-3x = -20
3x-y = 20 ...(1)
and also given that
y+10 = 2(x+10)
y+10 = 2x+20
y-2x = 10 ...(2)
By simultaneously solving equation(1) and equation(2)
y=70
Hence Akram's present age is 70 years..
Question No 24
The calendar for the year 2007 will be the same for the year ...
Select the correct answer
Solution!
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year 2007 has 1 odd day
2008 has 2 odd day
2009 has 1 odd day
2010 has 1 odd day
2011 has 1 odd day
2012 has 2 odd day
2013 has 1 odd day
2014 has 1 odd day
2015 has 1 odd day
2016 has 2 odd day
2017 has 1 odd day
Sum = 14 odd days = 0 odd days.
Hence, Calendar for the year 2018 will be the same as for the year 2007..
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year 2007 has 1 odd day
2008 has 2 odd day
2009 has 1 odd day
2010 has 1 odd day
2011 has 1 odd day
2012 has 2 odd day
2013 has 1 odd day
2014 has 1 odd day
2015 has 1 odd day
2016 has 2 odd day
2017 has 1 odd day
Sum = 14 odd days = 0 odd days.
Hence, Calendar for the year 2018 will be the same as for the year 2007..
Question No 27
What is the angle between the hands of a clock at 7:05 am?
Select the correct answer
Solution!
At 7:05 hour hand is nearly at 7
Minute hand is at 1
Angle between 7 and 1 is 180 degree.
Hour hand move 1/2 degree in one minute.
In 5 Minutes hour hand will move 1/2 * 5 = 2.5 degree
Hence, Angle between hands is 180 - 2.5 = 177.5 degree.
At 7:05 hour hand is nearly at 7
Minute hand is at 1
Angle between 7 and 1 is 180 degree.
Hour hand move 1/2 degree in one minute.
In 5 Minutes hour hand will move 1/2 * 5 = 2.5 degree
Hence, Angle between hands is 180 - 2.5 = 177.5 degree.
Question No 30
A * B means A is the sister of B , A $ B means B is the mother of A , A + B means A is the brother of B , A = B means B is the father of A ; Which of the following means M is the maternal uncle of N?
Select the correct answer
Solution!
No answer description available for this question..
No answer description available for this question..
Question No 37
Anil's swimming speed in still water is 14 km/h and speed of water is 4 km/h. How long will it take him to go upstream 50 km?
Select the correct answer
Solution!
Anil's swimming speed in still water = u = 14 Km/h
Speed of water = v = 4 Km/h
Total upstream speed = u-v = 14-10 = 10 Km/h
Distance to cover = S = 50Km
time = distance/speed
By putting values
time = t = 50/10 = 5 hours.
Anil's swimming speed in still water = u = 14 Km/h
Speed of water = v = 4 Km/h
Total upstream speed = u-v = 14-10 = 10 Km/h
Distance to cover = S = 50Km
time = distance/speed
By putting values
time = t = 50/10 = 5 hours.
Question No 40
A train travelling at he speed of 72km/h can cross a platform in 17 seconds. If length of the train is 180 meters, what is the length of the platform?
Select the correct answer
Solution!
Speed of train = v = 72Km/h = 72*(5/18) = 20m/s
Time = t = 17s
Length of the train = L1 = 180m
Length of the platform = L2 = ?
t = (L1+L2)/v
By putting values
17 = (180+L2)/20
340-180 = L2
L2 = 160m
Hence length of the platform is 160m..
Speed of train = v = 72Km/h = 72*(5/18) = 20m/s
Time = t = 17s
Length of the train = L1 = 180m
Length of the platform = L2 = ?
t = (L1+L2)/v
By putting values
17 = (180+L2)/20
340-180 = L2
L2 = 160m
Hence length of the platform is 160m..
Question No 43
The angle between the minute hand and the hour hand of a clock when the time is 4:20, is ?
Select the correct answer
Solution!
Angle traced by hour hand in 13/3 hrs = (360/12 * 13/3) = 130 degree
Angle traced by minute hand in 20 min = (360/60 * 20) = 120 degree
So, required angle = 130 - 120 = 10 degree.
Angle traced by hour hand in 13/3 hrs = (360/12 * 13/3) = 130 degree
Angle traced by minute hand in 20 min = (360/60 * 20) = 120 degree
So, required angle = 130 - 120 = 10 degree.
Question No 44
Sandeep's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1/5. What is Sandeep's father's age at present?
Select the correct answer
Solution!
Let the age of Sandeep and his father before 10 years be x and 5x respectively.
Given that Sandeep's age after six years will be three-seventh of his father's age
x + 16 = (3/7)(5x + 16)
7x + 112 = 15x + 48
8x = 64
x = 8
Sandeep's father's present age = 5x + 10
= 5*8 + 10 = 50.
Let the age of Sandeep and his father before 10 years be x and 5x respectively.
Given that Sandeep's age after six years will be three-seventh of his father's age
x + 16 = (3/7)(5x + 16)
7x + 112 = 15x + 48
8x = 64
x = 8
Sandeep's father's present age = 5x + 10
= 5*8 + 10 = 50.
Question No 47
X is 4 times as old as y. 4 years ago, X was 10 times as old as Y. What will be the ratio of their ages 6 years hence?
Select the correct answer
Solution!
Given that
X = 4Y ...(1)
and
X-4 = 10(Y-4)
X-4 = 10Y-40
X-10Y = -36
10Y-X = 36 ...(2)
Put value of X from equation(1) in equation(2)
10Y-4Y = 36
6Y = 36
Y = 6
Put value of Y in equation(1)
X = 4*6
X = 24
After 6 years
Y = 24+6
Y = 30
and
X = 6+6
X = 12
Ratio between X and Y is
30/12 = 5/2
Hence after 6 years ratio between ages of X and Y will be 5/2..
Given that
X = 4Y ...(1)
and
X-4 = 10(Y-4)
X-4 = 10Y-40
X-10Y = -36
10Y-X = 36 ...(2)
Put value of X from equation(1) in equation(2)
10Y-4Y = 36
6Y = 36
Y = 6
Put value of Y in equation(1)
X = 4*6
X = 24
After 6 years
Y = 24+6
Y = 30
and
X = 6+6
X = 12
Ratio between X and Y is
30/12 = 5/2
Hence after 6 years ratio between ages of X and Y will be 5/2..
Question No 48
A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
Select the correct answer
Solution!
Speed downstream = (5 + 1) kmph = 6 kmph
Speed upstream = (5 - 1) kmph = 4 kmph
Let the required distance be x km.
Then,
x/6 + x/4 = 1
2x + 3x = 12
5x = 12
Hence, x = 2.4 km.
Speed downstream = (5 + 1) kmph = 6 kmph
Speed upstream = (5 - 1) kmph = 4 kmph
Let the required distance be x km.
Then,
x/6 + x/4 = 1
2x + 3x = 12
5x = 12
Hence, x = 2.4 km.
Question No 51
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is
Select the correct answer
Solution!
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then,
(3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20
So, 3x + 10 = 70
and x + 10 = 30
Hence, ratio is 70/30 = 7/3..
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then,
(3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20
So, 3x + 10 = 70
and x + 10 = 30
Hence, ratio is 70/30 = 7/3..